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mafiozo [28]
3 years ago
13

Using the graphing function on your calculator, find the solution to the system

Mathematics
2 answers:
Mariulka [41]3 years ago
5 0

Answer:  The correct answer is:  x = 13/12, y= -3/4

Step-by-step explanation:

inessss [21]3 years ago
4 0
This is all I got sorry if it don’t help

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Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
W^2+4w+4/2w^2-8<br> Simplify the expression
4vir4ik [10]
The answer would be
3w {}^{2}   + 4w - 8
hope I helped
7 0
3 years ago
Read 2 more answers
Which inequality is the same as 7-2/b &lt;5/b
Stells [14]

Answer:

\large\boxed{0

Step-by-step explanation:

Domain:\ b\neq0\\\\7-\dfrac{2}{b}

7 0
3 years ago
Read 2 more answers
Is this Scientific Notation? 0.4 x 10^25
Mnenie [13.5K]
Yes that is scientific notation
8 0
3 years ago
Read 2 more answers
Hey, can you guys help me out with this question? I need the workings too.( find the surface area )
Ilia_Sergeevich [38]

▪︎Side 15 cm, 18 cm and x cm form a right angle triangle.

We know that :

=\tt  {hypotenuse}^{2}  =  {leg}^{2}   +  {leg}^{2}

Which means :

=\tt  {15}^{2}  +  {x}^{2}  =  {18}^{2}

=\tt 225 +  {x}^{2}  = 324

=\tt  {x}^{2}  = 324 - 225

= \tt {x}^{2}  = 99

\color{plum} =\tt x = 9.9 \: cm

Thus, x (radius) = 9.9 cm

We know that :

\color{hotpink}\tt \: Surface \:  area \:  of \:  cone \color{plum}=\pi r(r +  \sqrt{ {h}^{2}  +  {r}^{2} }

Then, the surface area of this cone :

= \tt3.14 \times 9.9 \times( 9.9 +  \sqrt{ {15}^{2}  +  {9.9}^{2} } )

=\tt 3.14 \times 9.9 \times( 9.9 +  \sqrt{323.01} )

=\tt 3.14 \times 9.9 \times (9.9 + 18)

=\tt 3.14 \times 9.9 \times 27.9

= \tt31.09 \times 27.9

\color{plum} =\tt\bold{ 867.4 \: cm}

Therefore, the surface area of this cone = 867.4 cm

5 0
2 years ago
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