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mote1985 [20]
3 years ago
11

An oblique square prism is shown. An oblique square prism is shown. The square has side lengths with a measure of x. The distanc

e between the bases is (x + 1). The top base extends to the right of the bottom base and is (x minus 2) units higher of the bottom base. Which expression represents the volume of the prism? x(x – 2) cubic units x(x +1) cubic units x2(x – 2) cubic units x2(x +1) cubic units
Mathematics
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

Your answer is C.) x2(x – 2) cubic units

On EDG

Step-by-step explanation:

Just took the test

Ivanshal [37]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Find the lateral area and the surface area of the right cone. Round your nearest answers to the nearest hundredth
S_A_V [24]

Step-by-step explanation:

Given that,

The height of the cone, h = 24 cm

The radius of the cone, r = 10 cm

The slant height of the cone is :

l=\sqrt{h^2+r^2} \\\\l=\sqrt{24^2+10^2} \\\\l=26\ cm

The lateral area of the cone is given by :

A=\pi rl\\\\=3.14\times 10\times 26\\\\=816.4\ cm^2\approx 816\ cm^2

The surface area of the cone is given by :

A=2\pi rh\\\\=2\times 3.14\times 10\times 24\\\\=1507.2 \approx 1507\ cm^2

5 0
3 years ago
Find the answer. Reduce fractions to lowest terms. Type the answer in the space provided
Delicious77 [7]

Answer:

17/30

Step-by-step explanation:

8/15/16/17

to make it easier it really is just multiplication you just have to flip the second fraction so it should be

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6 0
3 years ago
Givea)Possible number of positive real rootsb)Possible number of negative real rootsc)Possible rational roolsd)Find the roots
CaHeK987 [17]

The function is given to be:

x^3-2x^2-3x+6

QUESTION A

We can use Descartes' Rule of Signs to check the positive real roots of a polynomial.

The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number.

If we have:

f(x)=x^3-2x^2-3x+6

The coefficients are: +1, -2, -3, +6.

We can see that there are only 2 sign changes; from the first to the second term, and from the third to the fourth term.

Therefore, there are 2 or 0 positive real roots.

QUESTION B

To find the number of negative real roots, evaluate f(-x) and check for sign changes:

\begin{gathered} f(-x)=(-x)^3-2(-x)^2-3(-x)+6 \\ f(-x)=-x-2x^2+3x+6 \end{gathered}

The coefficients are: -1, -2, +3, +6.

We can see that there is only one sign change; from the second term to the third term.

Therefore, there is 1 negative real root.

QUESTION C

To check the possible rational roots, we can use the Rational Root Theorem since all the coefficients are integers.

The Rational Root Theorem states that if the polynomial:

P(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_2x^2+a_1x+a_0

has any rational roots, they must be in the form:

\Rightarrow\pm\mleft\lbrace\frac{factors\text{ of }a_0}{factors\text{ of }a_n}\mright\rbrace

From the polynomial, the trailing coefficient is 6:

a_o=6

Factors of 6:

\Rightarrow\pm1,\pm2,\pm3,\pm6

The leading coefficient is 1:

a_n=1

Factors of 1:

\Rightarrow\pm1_{}

Write in the form

\Rightarrow\mleft\lbrace\frac{a_o}{a_n}\mright\rbrace

Therefore,

\Rightarrow\pm(\frac{1}{1}),\pm(\frac{2}{1}),\pm(\frac{3}{1}),\pm(\frac{6}{1})

Therefore, the possible rational roots are:

\Rightarrow\pm1,\pm2,\pm3,\pm6

QUESTION D

We can use a graph to check the roots of the polynomial. The graph is shown below:

The roots of the polynomial refer to the points when the graph intersects the x-axis.

Therefore, the roots of the polynomial are:

x=-1.732,x=1.732,x=2

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(2,4) it takes 2 from -1 to 1 and 4 from -1 to 3
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