Step-by-step explanation:
This is the answer of this question.
Hey there! :)
Answer:
x = 242 mm.
Step-by-step explanation:
Begin by setting up a proportion between the actual college building and the drawing.
![\frac{22mm}{9m} = \frac{x}{99m}](https://tex.z-dn.net/?f=%5Cfrac%7B22mm%7D%7B9m%7D%20%3D%20%5Cfrac%7Bx%7D%7B99m%7D)
Cross multiply:
99 × 22 = 9 × x
2178 = 9x
Divide both sides by 9:
2178/9 = 9x/9
x = 242 mm.
5. since .6 is greater than 5, we round up.
Answer:
the area would be 0.4 or 40%
Step-by-step explanation:
The computation of the area is given below:
But before that the level of the density is
The density level is
= 1 ÷ (3 - 0)
= 1 ÷ 3
Area from 0 miles to 1.2 miles
= (1 ÷ 3) × (1.2 - 0)
= 0.4 or 40 %
Hence, the area would be 0.4 or 40%
the same is considered and relevant too