So 5 red cars
1/3 of all cars are red
therefor
5=1/3 of all cars
'of' means multply
5=1/3 times all cars
multiply both sides by 3
15=all cars
how many are left
basically how many are NOT red
15=all
red=5
all-red=others
15-5=others=10
10 cars are left
the question says that the total price equalled of the antiques is 70. It also says that she bought a table, which was 44, and 2 chairs (x). We can form this equation.
44 + 2x = 70. <------the 2x comes from 2 times the cost of one chair (x) and the . 44 comes from the cost of the table. The total is 70 dollars.
2x = 26 <-------solve algebraicelyy(sry about by spelling)
x = 13 <-------this is the cost of only one chair.
Answer: $13
Assuming that your own ticket is already secured.
From the 5 friends you can only choose 3.
The order in which these friends are chosen is not relevant. So this is a Combination problem.
Where the order is relevant the problem becomes a Permutation problem!
So the answer is 5 combination 3. = ⁵C₃
⁵C₃ = (5 * 4 * 3) / ( 3 * 2 * 1) = 10
You can take 10 groups of any 3 of your 5 friends.
Hi there!
x / 2 - 5 = 3
Begin by adding 5 to both sides to isolate for x:
x / 2 - 5 + 5 = 3 + 5
x / 2 = 8
Multiply both sides by 2 to have "x" alone on the left-hand side:
(x / 2) × 2 = 8 × 2
x = 16
