Answer:
a. 2
b. x^2 + 10x + 26
c. x^2 + 2x + 2
Step-by-step explanation:
For each part, replace x with the value you are given and simplify.
f(x) = x^2 - 2x + 2
a.
f(2) = 2^2 - 2(2) + 2 = 2
b.
f(x + 6) = (x + 6)^2 - 2(x + 6) + 2
= x^2 + 12x + 36 - 2x - 12 + 2
= x^2 + 10x + 26
c.
f(-x) = (-x)^2 - 2(-x) + 2
= x^2 + 2x + 2
Well you had x inches of snow in the beginning so
after monday it was
x+3
after wednesday
x+3+5=x+8
so the invers is the value that you use to get back to x
so if you now have x+8 than the inverse is -8
Firsly, the speed of Yochanan is not constant. So he has done a motion that contains an acceleration c.
for this type of movment, the equation is X= 1/2ct²+Vit
and with this last, we can find the equation of speed by dX/dt= ct + Vi
so v= ct+Vi
Vi the initial speed
<span>n average speed of 60 km/h until he got to school implies 60=ct+ 5,
</span>t =1.5 hour, so c= 60 - 5 / 1.5 = 56.66
and by using the formula during the motion with the bus)
V²f - V²i = 2. c (xf -xi) so V²f= 3600km/h V²i = 25 km/h
we can find xf -xi= V²f - V²i / 2c, and <span>xf -xi= 31.54 km
</span> but the total distance is 35 km,
so 35km - 31.54km = 3.45 km
yochanan coverd 3.45 kmby walking
yochanan coverd <span>31.54 km </span>km by riding bus
Answer:
A)
B) t > s
Step-by-step explanation:
Attached below is a detailed solution of the given problem
Given equation:
dy/dt + ay = with Y(c) = 0
A) Determine the solution
B) Determine the solution