What do you think will be the most challenging goal for you, and why?

Advanced Placement (AP)

1 answer:

8_murik_8 [283]3 years ago

6 0

Answer:

Well this is up to you! This is your challenge, but i'll give my opinion.

Explanation:

For me, the most challenging goal for me is social goal, I put my friends over EVERYTHING, sometimes even family. That is something I am slowly working on but that is my main challenge, I distract myself with friends.

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Helppp quick pointsss

Margaret [11]

Answer:

1) The angle would be 150 degrees

a) coordinates would be ( $-\frac{\sqrt{3}}{2}$ , $\frac{1}{2}$ )

b) Trigonometric ratios:

sin: $\frac{1}{2}$

cos: $-\frac{\sqrt{3}}{2}$

tan: $-\frac{\sqrt{3}}{3}$

csc: 2,

sec: $-\frac{2\sqrt{3}}{3}$

cot: $\sqrt{3}$

Explanation:

$\frac{17\pi }{6}$ simplifys to $\frac{5\pi }{6}$ which has a reference angle of $\frac{\pi }{6}$ . We can take the coordinates of $\frac{\pi }{6}$ and make the x value negative to find the correct coordiantes. Then, using those coordinates, plug the into the trigonomic equations.