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natali 33 [55]
3 years ago
8

One survey showed that among 785 randomly selected subjects who completed four years of college, 18.3% smoke and a 98% confidenc

e interval for the true percentage of smokers among all people who completed four years of college is 15.1% to 21.6%. Based on the result, the smoking rate for those with four years of college appears to be substantially different than the 27% rate for the general population.
a. Trueb. False
Mathematics
1 answer:
Valentin [98]3 years ago
6 0

Answer

a. True

Step-by-step explanation:

Based on this survey we estimate that about 18.3\% of the college students smokes. And a 98\% confidence interval is [15.1\% ; 21.6\%].  So we know that our estimative for the smoking rate is in the confidence interval with 98\% certainty. We also know the estimative for the smoking rate in the general population is 27\%. So we can write the two possible hypothesis:

H_0 = Smoking rate is equal to 27\%.

H_1 = Smoking rate is not equal to 27\%.

We will reject the null hypothesis (H_0) if the estimate doesn't fall into the confidence interval for the college students smoking rate.

Since this condition holds we reject the null hypothesis. So with 98\% certainty we say that the smoking rate for the general population is different than the smoking rate for the college students.

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In the first quadrant you start at 7,5 and move 4units left and 1 unit down
Elenna [48]

Answer:

(3,4)

Step-by-step explanation: I'm assuming you want to know the final point you end up at. The first part of our coordinate pair is our x value, so we want to reduce our x-value by 4 to go left 4 units, the second part is our y-value, we want to reduce it by 1 to go down 1 unit. So, our final coordinate pair is (7-4,5-1) or (3,4).

7 0
4 years ago
How to do question 1?Had no idea how to do both parts
givi [52]
y=\dfrac{\ln x}{3x-6}

Differentiate both sides with respect to x:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}

When x=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13

For part (b), we now assume that x and y are functions of an independent variable, which we'll call t (for time). Now differentiating both sides with respect to t, we have

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}

where the chain rule is used on the right side. We're told that y is decreasing at a constant rate of 0.1 units/second, which translates to \dfrac{\mathrm dy}{\mathrm dt}=-0.1. So when x=1, you have

-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}
-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}
\dfrac{\mathrm dx}{\mathrm dt}=0.3

where the unit is again units/second.
6 0
3 years ago
A=1/7(b+c-d) solve for b
castortr0y [4]

Step-by-step explanation:

ax7=7 x 1/7(b+c-d)

7a=b+c-d

7a-c+d=b

b=7a-c+d

8 0
3 years ago
What is 4 + 8 divided by 2 x (6 - 3) = ? what does ? equal? ? =__
Levart [38]

Answer:

4+8/2*(6-3)

4 + 8/2* 3

4+4*3

4+12

16

Step-by-step explanation:

5 0
3 years ago
For employees at a large company, the mean number of overtime hours worked each week is 9.2 hours with a population standard dev
topjm [15]

Answer:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

Step-by-step explanation:

For this case we have the following parameters given:

\mu = 9.2 , \sigma =1.6

We select a ample size of n=49. And we want to find this probability:

P(\bar X> 9.3)

And for this case is a right tail probability and we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

8 0
3 years ago
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