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2 years ago

If 5= 5+2x then 12x= ? I’m

Mathematics

2 answers:

julsineya [31]2 years ago

7 0

Answer:

12x = 0

Step-by-step explanation:

5= 5+2x

Subtract 5 from each side

5-5= 5-5+2x

0 = 2x

Multiply each side by 6

0*6 = 2x*6

0 = 12x

Artist 52 [7]2 years ago

7 0

Answer:

12x = 0

Step-by-step explanation:

Let's first find x:

5 = 5 + 2x

Subtract 5 from both sides. Since both sides are equal, subtracting the same from each side will still leave both sides equal.

5 = 5 + 2x

5 - 5 = 5 + 2x - 5

Since 5-5 = 0:

0 = 5 + 2x - 5

0 = 5 - 5 + 2x

Again, 5-5 = 0:

0 = 0 + 2x

0 = 2x

Dividing both sides by 2:

0/2 = 2x / 2

0 = x

x = 0

As we can see, x = 0.

Thus, 12x must also be 0:

12x

Putting in x = 0:

12 * 0 = 0

Answer: 12x = 0

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Using Cramer's rule to solve linear systems.

Rzqust [24]

Answer: Last Option

$x=2,\ y=-5$

Step-by-step explanation:

Cramer's rule says that given a system of equations of two variables x and y then:

$x =\frac{Det(A_X)}{Det(A)}$

$y =\frac{Det(A_Y)}{Det(A)}$

For this problem we know that:

$Det(A) = |A|=\left|\begin{array}{ccc}4&-6\\8&-2\\\end{array}\right|$

Solving we have:

$|A|= 4*(-2) -(-6)*8\\\\|A|=40$

$Det(A_X) = |A_X|=\left|\begin{array}{ccc}38&-6\\26&-2\\\end{array}\right|$

Solving we have:

$|A_X|=38*(-2) - (-6)*26\\\\|A_X|=80$

$Det(A_Y) = |A_Y|=\left|\begin{array}{ccc}4&38\\8&26\\\end{array}\right|$

Solving we have:

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Finally

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$y =\frac{|A_Y|}{|A|} = \frac{-200}{40}\\\\y=-5$

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