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Afina-wow [57]
2 years ago
12

If 5= 5+2x then 12x= ? I’m

Mathematics
2 answers:
julsineya [31]2 years ago
7 0

Answer:

12x = 0

Step-by-step explanation:

5= 5+2x

Subtract 5 from each side

5-5= 5-5+2x

0 = 2x

Multiply each side by 6

0*6 = 2x*6

0 = 12x

Artist 52 [7]2 years ago
7 0

Answer:

12x = 0

Step-by-step explanation:

Let's first find x:

5 = 5 + 2x

Subtract 5 from both sides. Since both sides are equal, subtracting the same from each side will still leave both sides equal.

5 = 5 + 2x

5 - 5 = 5 + 2x - 5

Since 5-5 = 0:

0 = 5 + 2x - 5

0 = 5 - 5 + 2x

Again, 5-5 = 0:

0 = 0 + 2x

0 = 2x

Dividing both sides by 2:

0/2 = 2x / 2

0 = x

x = 0

As we can see, x = 0.

Thus, 12x must also be 0:

12x

Putting in x = 0:

12 * 0 = 0

Answer: 12x = 0

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A survey of high school juniors found that 82% of students plan on attending college. If you pick three students at random, what
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6 0
3 years ago
Read 2 more answers
The members of a high school band asked a number of students whether they would like blue, gold, or both for the uniforms for th
MaRussiya [10]

The values of a and b are a = 33% and b = 43% ⇒ last answer

Step-by-step explanation:

The venn-diagram contains:

  • A circle labeled blue 32
  • A circle labeled gold 25
  • The two circles are overlap with label 12 on the overlap

The table:

→ Band  :  blue  :  N.b  : total

→ gold   :  16%   :  a      :  49%

→ N.g     :  b       :  8%   :  51%

→ Total  :  59%  :  41%  :  100%

We need to find the values of a and b

From the table

16% represents the percentage of blue and gold uniforms (2nd row with 2nd column)

From venn-diagram

The common part of blue and gold label with 12 (overlap of two circles)

∴ 16% of the total number of students = 12

∵ 16% × x = 12

∴ \frac{16}{100} × x = 12

∴ 0.16 x = 12

- Divide both sides by 0.16

∴ x = 75

∵ x represents the total number of students

∴ The total number of students were asked is 75

From the table

b represents the percentage of blue but not gold uniforms (3rd row and 2nd column)

From venn-diagram

The part that has blue and not gold labeled with 32 (the part of the blue circle not in the gold circle)

∴ 32 of the total number of students like the blue but not gold

- Divide 32 by the total 75 , then multiply the quotient by 100%

   to find the percentage of blue but not gold

∴ b = \frac{32}{75} × 100% = 42.6666%

∴ b ≅ 43%

From the table

a represents the percentage of gold nut not blue uniforms (2nd row and 3rd column)

From venn-diagram

The part that has gold and not blue labeled with 25 (the part of the gold circle not in the blue circle)

∴ 25 of the total number of students like the gold but not blue

- Divide 25 by the total 75 , then multiply the quotient by 100%

   to find the percentage of gold but not blue

∴ a = \frac{25}{75} × 100% = 33.3333%

∴ a ≅ 33%

The values of a and b are a = 33% and b = 43%

To check your answer complete the table you will find the total of it is 100% ( for the columns 16% + 43% = 59% , 33% + 8% = 41% , then 59% + 41% = 100%, for the rows 16% + 33% = 49% , 43% + 8% = 51% , then 49% + 51% = 100%)

Learn more:

You can learn more about the probability in brainly.com/question/3756853

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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4 0
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PLEASE HELP!!!!! What is the value of x in the matrix equation below?
Brums [2.3K]

The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

3 0
3 years ago
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