Answer:
![\sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Step-by-step explanation:
At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:
![\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%5Csqrt%20%5B4%5D%20%7Bx%5E2%7D%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%5Ccdot%20x%7D%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Alternatively, if you're allowed to use rational exponents, we can convert everything:
![\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20x%5E%7B%5Cfrac12%7D%20%5Ccdot%20x%5E%5Cfrac14%20%3D%20x%5E%7B%5Cfrac12%20%2B%5Cfrac14%7D%3D%20x%5E%7B%5Cfrac24%20%2B%5Cfrac14%7D%3D%20x%5E%5Cfrac34%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
The area of a rectangular prism is 200 so I divided 600 by 3 and so the possible dimensions are 200 by 200 by 200.
315 m²
<u><em>area of rec + area of rec + area of rec + area of triangle</em></u>
⇒ length + width + length + width + length + width + 1/2 * base * height
⇒ 19 * 6 + 9 * 9 + 18 * 5 + 1/2 * 12 * 5
⇒ 90 + 30 + 81 + 114
⇒ 315 m²
Answer: Total Volume = 15π + 18 π= 33π cubic mm
Step-by-step explanation:
What is the volume of the composite figure? Leave the answer in terms of π.
_33π mm3
We have a cone here conjoined to a semi-sphere.
so
Cone volume: C = (1/3)*(πr^2) * h
semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)
r = 3 mm and h = 5mm
so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm
V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm
Total Volume = 15π + 18 π= 33π cubic mm
Answer:
(a) 169.1 m
Step-by-step explanation:
The diagram shows you the distance (x) will be shorter than 170 m, but almost that length. The only reasonable answer choice is ...
169.1 m
__
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
The leg of the right triangle adjacent to the marked angle is x, and the hypotenuse is 170 m. Putting these values into the equation, you have ...
cos(6°) = x/(170 m)
x = (170 m)cos(6°) ≈ (170 m)(0.994522) ≈ 169.069 m
The horizontal distance covered is about 169.1 meters.
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<em>Additional comment</em>
Expressed as a percentage, the slope of this hill is tan(6°) ≈ 10.5%. It would be considered to be a pretty steep hill for driving.
