Answer:
Amount he must have in his account today is $5,617.92
Step-by-step explanation:
Data provided in the question:
Regular withdraw amount = $900
Average annual interest rate, i = 4% = 0.04
Time, n = 7 years
Now,
Present Value = ![C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)](https://tex.z-dn.net/?f=C%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1-%281%2Bi%29%5E%7B-n%7D%7D%7Bi%7D%20%5Cright%5D%20%5Ctimes%281%20%2B%20i%29)
here,
C = Regular withdraw amount
Thus,
Present Value =
Present Value = ![900 \times\left[ \frac{1-(1+0.04)^{-7}}{ 0.04 } \right] \times(1 + 0.04)](https://tex.z-dn.net/?f=900%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1-%281%2B0.04%29%5E%7B-7%7D%7D%7B%200.04%20%7D%20%5Cright%5D%20%5Ctimes%281%20%2B%200.04%29)
Present Value = ![936 \times\left[ \frac{1 - 1.04^{-7}}{ 0.04} \right]](https://tex.z-dn.net/?f=936%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1%20-%201.04%5E%7B-7%7D%7D%7B%200.04%7D%20%5Cright%5D)
Present Value = ![936 \times\left[ \frac{1 - 0.759918}{ 0.04} \right]](https://tex.z-dn.net/?f=936%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1%20-%200.759918%7D%7B%200.04%7D%20%5Cright%5D)
Present Value = 936 × 6.00205
or
Present Value = $5,617.92
Hence,
Amount he must have in his account today is $5,617.92
Divide the total portion (9 1/2 cups) by the portion size (3/4 cup).
=9 1/2 ÷ 3/4
convert 9 1/2 to improper fraction
=19/2 ÷ 3/4
to divide fractions, multiply by the reciprocal/inverse of 3/4
=19/2 * 4/3
multiply numerators; multiply denominators
=(19*4)/(2*3)
=76/6
=12.666666
ANSWER: The greatest number he can offer servings to is C) 12
Hope this helps! :)
Answer:
Step-by-step explanation:
<u>Initial coordinates and transformations:</u>
- (x, y) → (4x, 4y) → (3x, 3y)
- A(-1, -1) → A'(-4, -4) → A''(-3, -3)
- B(1, 1) → B'(4, 4) → B''(3, 3)
- C(2, 0) → C'(8, 0) → C''(6, 0)
Answer:
<h3>160</h3>
Step-by-step explanation:
Divide 7,200 by 45
Answer: increased
Step-by-step explanation:
- An x% confidence interval indicates that a person can be x% confident that true population parameter lies in it.
More level of confidence more width of the interval.
As level of Confidence interval increases width of interval increases.
Width of interval 
level of Confidence interval
So, If a 95% confidence interval had been constructed instead of 90% the width of the interval would have been<u> increased.</u>
