Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
The perimeter of a rectangle is twice the sum of length and width, so the sum of length and width is half the perimeter, 10 3/4 ft.
The width will be the difference between this and the length, hence 5 1/2 ft.
The area is the product of length and width.
A = length×width
A = (5.25 ft)×(5.5 ft) = 28.875 ft²
The area of the sandbox is 28 7/8 ft².
Answer:
From the first bag the probability is 5 out of 15 or 1/3 simplified
The second bags probability is 4 out of 9
All the bags combined the probability is 9 out of 24
Step-by-step explanation:
The probability should be set up by putting the blue marbles as the numerator and the sum of all the marbles combined for the denominator
With everything said all you have to do is figure out the two steps an you’re good to go
Answer: isosceles
Step-by-step explanation:
By the alternate interior angles theorem, 
Since angles in a triangle add to 180 degrees, 
Since sides opposite equal angles in a triangle are equal,
.
So, triangle ABC is <u>isosceles</u>
Answer:
10
Step-by-step explanation:
Let c = sum of ages of all children.
mean age of all children = c/15 = 7
c = 15 * 7 = 105
The sum of the ages of all children is 105.
Let b = sum of ages of the 9 boys.
mean age of boys = b/9 = 5
b = 9 * 5 = 45
The sum of the ages of the boys is 45.
The sum of the ages of the girls is c - b.
c - b = 105 - 45 = 60
The number of girls is 15 - 9 = 6
mean age of girls = (sum of ages of the girls)/(number of girls) =
= 60/6 = 10