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2 years ago

Find the sum of (x+5), (-4x-2), and (2x-1) Show your work please

Mathematics

2 answers:

Papessa [141]2 years ago

7 0

Sum means add
(x+5) + (-4x-2) + (2x-1)
=-3x+3+(2x-1)
=-x+2

Bess [88]2 years ago

6 0

Answer:-x+2

because you can do it two ways. You could have either done it my way.Step-by-step explanation:

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Step-by-step explanation:

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Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

Separate the solutions

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

Separate the real and imaginary parts

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

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2 years ago

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frez [133]

Answer:

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Step-by-step explanation:

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the perimeter of a triangle = sum of the side lengths

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