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2 years ago

GETTING RID OF MY ACCOUNT MIGHT AS WELL DO IT WITH SOME FUN

Advanced Placement (AP)

2 answers:

Hatshy [7]2 years ago

6 0

I have no idea how to answer this but i built a satanic basement on my brother roblox account and now hes crying (:

kramer2 years ago

6 0

One day on a war ship there was an enemy ship on the horizon and the captain said bring me my red shirt

The crew brought him his red shirt

When the fight was over the crew asked why did you want your red shirt

The captain replied because if i got shot i didn't want you to stop fighting and help me

The crew said nothing

The next morning the crew was yelling 20 SHIPS ON THE HORIZON

The captain replied with "bring me my brown pants."

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APES + WILL GIVE BRAINLIST WHEN CAN + 30 POINTS PER PERSON I BELIEVE. PLEASE HELP

Misha Larkins [42]

Answer:

the Mississippi watersheds effetces mat affet watersheds diepicted in pthe picture of china

5 0

1 year ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

8 0

1 year ago

Why did she leave I really liked her she was the one

SpyIntel [72]

You should’ve stayed .. were you goin through sum at the time ??? txt her now !!

8 0

2 years ago

Read 2 more answers

Identify the property that justifies the statement: 5(x-3)=x-15

Bond [772]

I don't know if you mean the equation simplified, but the first property to any equation or expression is "given." (without the quotation marks, of course.)

7 0

2 years ago

All galaxies are held together by gravity, but based on what we can see (stars, nebulae, etc.) , there shouldn’t be enough gravi

gizmo_the_mogwai [7]

Answer:

Nebular

Explanation:

8 0

2 years ago

Read 2 more answers