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Minchanka [31]
3 years ago
6

What is the value of the expression 3y-4xy^2 when x=3 and y=-6

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0
-450 and can i get brainliest
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The distance formula has its roots in the Pythagorean theorem. True Or False
Novay_Z [31]
The correct answer for the given statement above would be TRUE. It is true that the distance formula has its roots in the Pythagorean theorem or it is derived from the Pythagorean theorem. <span>The </span>distance formula<span> is used to find the distance between two points in the coordinate. Hope this is the answer that you are looking for.</span>
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4 years ago
Write each decimal as a percent.
Mumz [18]
1. 74%
2. 15%
3. 9%
4. 61.7%
5. 83.4%

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3 years ago
Read 2 more answers
Find the domain and range of the relation. Also determine whether the relation is a function.
OLEGan [10]

Answer:

The relation is a function!

Your Domain should be...

{-1, 1, 7, 9}

Your Range should be...

{-1, 8, 9}

WHY?

Your domain is always your x-coordinates, which are the first coordinates in a pair.

Your range is always your y-coordinates, which are the second coordinates in a pair.

When listing the points, it's important to remain a relation CANNOT be a function if the x's repeat, so luckily, they do not repeat.

Also, when listing points for your range, remember, if they repeat, you should only count one of the numbers, as you can see from the answer, there was two nines, but instead I put one.

5 0
3 years ago
Quadrilateral ABCD is inscribed in circle as shown. What is the value of y?
julsineya [31]
The value of y is 83 degrees because any quadrilaterals opposite sides or angles are equal and opposite (or diagonal) from point D.

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7 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
1 year ago
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