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tamaranim1 [39]
4 years ago
10

Solve: X+14.91=59.67

Mathematics
1 answer:
Anton [14]4 years ago
7 0
Hihi!

The answer to X+14.91=59.67 would be X= 44.76! This is because you would take 14.91 ÷ X = 59.67

I hope I helped!
-Jailbaitasmr
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A sin^3theta+b cos^3theta=sintheta costheta and a sintheta-b costheta=0 then prove a^2+b^2=1​
frozen [14]

Answer:

<em>Proof in explanation</em>

Step-by-step explanation:

<u>Trigonometric Identities</u>

The basic trigonometric identity is:

\sin^2\theta+\cos^2\theta=1

We'll use it and some basic algebra to prove that, given:

a sin^3\theta+b cos^3\theta=sin\theta cos\theta

And

a\sin\theta-b\cos\theta=0

Then

a^2+b^2=1

From the equation:

a\sin\theta-b\cos\theta=0

We have:

a\sin\theta=b\cos\theta\qquad [1]

The equation

a sin^3\theta+b cos^3\theta=sin\theta cos\theta

Can be rewritten as

a\sin\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta

Replacing [1]:

b\cos\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta

Taking the common factor:

b\cos\theta (\sin^2\theta+ \cos^2\theta)=\sin\theta \cos\theta

The expression in parentheses is 1, thus:

b\cos\theta =\sin\theta \cos\theta

Dividing by \cos\theta

b=\sin\theta

Replacing in

a\sin\theta=b\cos\theta

We have

a\sin\theta=\sin\theta\cos\theta

Dividing by \sin\theta

a=\cos\theta

Now:

a^2+b^2=(\cos\theta)^2+(\sin\theta)^2

This expression is 1, thus it's proven:

\boxed{a^2+b^2=1}

6 0
3 years ago
Hi. I need help wih this question (see image). Please show workings.<br>​
Kipish [7]

Answer:

\frac{dy}{dx} = 12x³ - 6x² - 7

Step-by-step explanation:

Differentiate each term using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1}

Given

y = 3x^{4} - 2x³ - 7x + 5, then

\frac{dy}{dx} = 4.3x^{4-1} - 3.2x^{3-1} - 7x^{1-1} + 0

   = 12x³ - 6x² - 7

4 0
3 years ago
Give the number that is 2 less than its own absolute value
nexus9112 [7]

Answer:

-1

Step-by-step explanation:

l -1 l = 1

1 - -1 = 2

i HOPE U UNDERSTOOD!! :)

4 0
3 years ago
Solve by completing the square: x2+4x-5=0
Sidana [21]

Answer:

The solutions are {-5, 1}

Step-by-step explanation:

Next time, please use the symbol " ^ " to denote exponentiation:

x^2+4x-5=0

Start by identifying the coefficient of the x term (it is 4 here).  Divide this by 2, resulting in 2.  Square this result (square 2), obtaining 4.

Now add this 4 after the 4x term, and then subtract this 4:

x^2+4x  +4  - 4  -5=0

Rewrite x^2+4x + 4 as (x + 2)²:

(x + 2)² - 9 = 0

Add 9 to both sides, to isolate (x + 2):

(x + 2)²  = 9

Take the square root of both sides:

x + 2 = ±3

Solve for x:  x = -2 + 3, or 1

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The solutions are {-5, 1}

3 0
4 years ago
Joint-Serve Prosthetics spends 43% of its total expenses for payroll. It increased its total expenses when it spent $250,000 for
Leni [432]
Answer: $2,150,000

Explanation: Let

T = Total expenses of Joint-Serve

Then, before the company acquired robotic assemblers, the expenses allocated for payroll is given by

Expenses for Payroll = 43% of Total Expenses
Expenses for Payroll = 0.43T     (1)
(Because 43% = 0.43)

Because the total expenses increased by $250,000 after spending for robotic assemblers, the total expenses = T + 250,000

So, the payroll expense is now calculated as

Expenses for Payroll = 38% of Total Expenses
Expenses for Payroll = 0.38(T + 250,000)     (2)
(Because 38% = 0.38 and total expenses = T + 250,000)

By comparing equations (1) and (2),

0.43T = 0.38(T + 250,000)&#10;\\ 0.43T = 0.38T + 0.38(250,000)&#10;\\ 0.43T = 0.38T + 95,000&#10;\\ 0.43T - 0.38T = 95,000&#10;\\  \frac{0.05T}{0.05}  =  \frac{95,000}{0.05} &#10;\\ \boxed{T = \$ 1,900,000}

Thus, the total expense before the purchase of robotic assemblers is T = $ 1,900,000. Therefore, the total expense after purchasing the robotic assemblers is T + 250,000 = 1,900,000 + 250,000 = $2,150,000  
6 0
3 years ago
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