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oksano4ka [1.4K]
3 years ago
7

How many packages of hamburger buns and meat patties should you buy to sell at a baseball tournament?

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
13 packs of meat patties and 16 packs of buns
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Please help, I will give brainliest to whoever helps!
jeka94
This is for problem 54
6 0
2 years ago
If I have 10 dollars and I win 6 out of 10 and lose 4 out of 10 and bet 1$ each trade, how much should there be left after 10 tr
ololo11 [35]

you will be left with 12 dollars.

<u> </u><u>Step-by-step explanation: </u>

Given:

The actual money you have = 10 dollars.

The bet amount for each trade= 1$

For each win, you get extra +1 dollar.

Step 1:

So, you won 6 trades= (6*1)= 6$

Step 2:

For each lose, you loss -1 dollar.

Step 3:

So, you lose 4 trades= (4)*(-1)= -4$

Step 4:

After 10 trades, the money you earned is= 6$ -4$= 2 dollars.

Finally, the total money left after 10 trades is= actual money + earned money                                                

= $10 + $2= 12 dollars.

7 0
3 years ago
X-14
DENIUS [597]

Step-by-step explanation:

it will be 14 times 2 which will be 28 length and 74 plus 74 which will be 148 for the both side wide.

7 0
3 years ago
What is the solution to the following equation?
nexus9112 [7]

Answer:

The answer to your question is the letter B. x = 6

Step-by-step explanation:

Data

               4x² - 48x = -144

Process

1.- Equal to zero

               4x² - 48x + 144 = 0

2.- Multiply 4 by 144

             4 x 144 = 576

3.- Find the prime factors of 576

                     576   2

                     288   2

                     144    2

                       72    2

                       36   2

                       18    2

                        9    3

                        3     3

                         1

4.- Find two numbers that added gives -48,

     these numbers are -24 and -24

5.- Write the equation using these numbers

              4x² -24x - 24x + 144 = 0

6.- Factor by grouping

             4x(x - 6) - 24(x - 6)

7.- Factor by like terms

             (x - 6)(4x - 24)

8.- Find the solutions

              x - 6 = 0           4x - 24 = 0                            

              x = 6                   4x = 24

                                        x = 24/4

                                        x = 6

8 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
2 years ago
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