x^2 + 6xy + 8y2
4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
Combine like terms:
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)
= -x^2 + 6xy + 8y^2
64
80 80
thats how you havw to put it
Answer:
-10, -3, 5, 16
Step-by-step explanation:
even though the negative number (10) might seem big, but its not
I can't draw a picture but the little hand would be on the 6 and the big hand would be on the 1.
