A is the answer i’m pretty sure.
1. LI = 12
2. TV = 8.75, X = 9.75
3. No, it would be if AD = 15, DB = 12 and AE = 10, EC = 8.
4. No, CE needs to = 1/2 of AE, not 1/3.
5. Yes, DB and EC are each 1/3 of AB and AC.
6. X = 15
7. X = 9
8. X = 8
Answer:
This unit discusses areas of paralelograms, triangles, trapezoids, rhombuses, kites, and regular polygons.
Step-by-step explanation:
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>