Answer:
A.O(1)
Explanation:
In the implementation of queue by using linked chain the performance of the enqueue operation is O(1).We have to maintain two pointers one head and the other tailand for enqueue operation we have to insert element to the next of the tail and then make that element tail.Which takes O(1) time.
Answer:
class Main {
public static void printPattern( int count, int... arr) {
for (int i : arr) {
for(int j=0; j<count; j++)
System.out.printf("%d ", i);
System.out.println();
}
System.out.println("------------------");
}
public static void main(String args[]) {
printPattern(4, 1,2,4);
printPattern(4, 2,3,4);
printPattern(5, 5,4,3);
}
}
Explanation:
Above is a compact implementation.
D. Rise of NASA.Hope I helped.
The answer is c because the perpendicular bicector alligns.
Here i found this link that might help!
https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html
Have a nice day!
