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jonny [76]
3 years ago
8

A bluetooth device in ____ mode is part of the piconet but is in a low-power state.

Computers and Technology
1 answer:
adelina 88 [10]3 years ago
7 0
A bluetooth device in park/hold mode is part of the piconet but is in a low-power state. These are power saving modes of operation for Bluetooth devices which are connected to a piconet and  are used when no data is to be transmitted.The hold mode is used when connecting several piconets or managing a low-power device such as temperature sensor. When the park mode is used t<span>he device is still synchronized to the piconet but does not participate in traffic.</span>
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Plz help, correct answer will get brainliest (if i can, if i can't ill still rate and give thanks)
Elena-2011 [213]

Answer:

E-book : online edition of a new novel .

e-zine:online issue of today’s newspaper.

Online reference: online encyclopedia

blog: online website that posts restaurants reviews

Explanation:

Are you doing edge?

Also pleaseeeeeeeeeeeeeeeeeee mark me brainliest.

6 0
2 years ago
Write a program that replaces words in a sentence. The input begins with an integer indicating the number of word replacement pa
kramer

Answer: provided in the explanation segment

Explanation:

This is the code to run the program:

CODE:  

//Input: 3 automobile car manufacturer maker children kids

  //15 The automobile manufacturer recommends car seats for children if the automobile doesn't already have one.

  import java.util.Scanner;

  public class LabProgram{

  public static int findWordInWordList(String[] wordList, String wordToFind, int numInList) {

          for (int i = 0; i < numInList; i++) {

              if (wordList[i].equals(wordToFind)) {

                  return i;

              }

          }

          return -1;

      }

      public static void main(String[] args) {

          Scanner scan = new Scanner(System.in);

          String[] original_String = new String[20];

              String[] modified_String = new String[20];

          int numInList = scan.nextInt();

          for (int i = 0; i < numInList; i++) {

              original_String[i] = scan.next();

              modified_String[i] = scan.next();

          }

          int num_Of_Words = scan.nextInt();

          String[] words_To_Replace = new String[num_Of_Words];

          for (int i = 0; i < num_Of_Words; i++) {

              words_To_Replace[i] = scan.next();

          }

          int indx;

          for (int i = 0; i < num_Of_Words; i++) {

              indx = findWordInWordList(original_String, words_To_Replace[i], numInList);

              if (indx != -1)

                  words_To_Replace[i] = modified_String[indx];

          }

          for (int i = 0; i < num_Of_Words; i++)

              System.out.print(words_To_Replace[i] + " ");

          System.out.println();

      scan.close();

      }

  }

cheers i hope this helps!!!!1

3 0
3 years ago
Which blog had legal content and is written mostly by lawyers
Svetradugi [14.3K]
Is it asking for a web site like .edu? or something like that?
6 0
3 years ago
Read 2 more answers
You want to allow members of the users group to use fdisk on the /dev/sda drive (and only that drive) and to use the yum command
masya89 [10]

Answer:

su ,sg and sudo command.

Explanation:

Whenever the user needs to enable workgroup mates should use fdisk including just that disk on both the /dev / sda disk, using the following command to update and configure the following packages. Thus he uses the command su, sg, and sudo.

So, the following commands are required according to the following statement.

6 0
3 years ago
Leslie Is doing a sociological study of people who have live remote island. She interviews the people and than she observes them
dimulka [17.4K]
Making guesses, as opposed to the other answers, this is the only one that forges new ideas and doing such will only lead to an illegitimate conclusion/study.
5 0
2 years ago
Read 2 more answers
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