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2 years ago

Fraction less than 3/6

Mathematics

2 answers:

fredd [130]2 years ago

8 0

2/6 would be less than 3/6

lys-0071 [83]2 years ago

7 0

Well you shaded in two of the six, so it is 2/6.

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A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

creativ13 [48]

Answer:

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

$r=\frac{18}{2+\theta}$

step 2

Find the value of s

$s=r \theta$

substitute the value of r

$s=\frac{18}{2+\theta}\theta$

step 3

we know that

The area of complete circle is equal to

$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

6 0

3 years ago

6 • 14 - (9 + 8) 2 =

Nataly [62]

Answer:

Step-by-step explanation:

For this question you would follow the BIDMAS rule - (Brackets, Indices, Division, Multiplication, Addition, Subtraction.)

The first thing in this question you need to solve it (9 + 8)

we do this because, when we follow BIDMAS, the first rule is brackets

so, 9 + 8 = 17

The second step is to multiply, as this rule is second,

so, 17 x 2 = 34

Our final step is to solve the last bit, which is 6 x 14

and we know that 6 x 14 = 84

So now that we have 84 and 34, we need to subtract the two numbers as shown,

84 - 34 = 50

And this is how you get the answer 50

i hope this has helped you, please comment if you did not understand it and i will explain it in another way : )

4 0

3 years ago

Read 2 more answers

Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same

Hoochie [10]

we have

$y=\frac{2}{5}x-5$

Let's Isolate the variable y in each of the cases and then compare with Fiona's equation to determine the solution of the problem

case A) $x-\frac{5}{4}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-5y= 25$

$5y=4x-25$

Divide by $5$ both sides

$y=\frac{4}{5}x-5$

therefore

the case A) is not equal to Fiona's equation

case B) $x-\frac{5}{2}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-10y= 25$

$10y=4x-25$

Divide by $10$ both sides

$y=\frac{2}{5}x-2.5$

therefore

the case B) is not equal to Fiona's equation

case C) $x-\frac{5}{4}y= \frac{25}{2}$

Multiply by $4$ both sides

$4x-5y= 50$

$5y=4x-50$

Divide by $5$ both sides

$y=\frac{4}{5}x-10$

therefore

the case C) is not equal to Fiona's equation

case D) $x-\frac{5}{2}y= \frac{25}{2}$

Multiply by $2$ both sides

$2x-5y= 25$

$5y=2x-25$

Divide by $5$ both sides

$y=\frac{2}{5}x-5$

therefore

the case D) is equal to Fiona's equation

<u>the answer is</u>

$x-\frac{5}{2}y= \frac{25}{2}$

7 0

3 years ago

Read 2 more answers

One degree Celsius indicates the same temperature change as

Romashka [77]

D. one kelvin is the answer

4 0

3 years ago

Solve by factoring the equation x^2+36=12x

Fudgin [204]

$x^2+36=12x\\\\x^2-12x+36=0\\\\x^2-6x-6x+36=0\\\\x(x-6)-6(x-6)=0\\\\(x-6)(x-6)=0\\\\(x-6)^2=0\iff x-6=0\Rightarrow\boxed{x=6}$

6 0

3 years ago