First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
Answer:
D
Step-by-step explanation:
2 terms
Answer:
x = 32°
Step-by-step explanation:
∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.
m<KML = m<KLM = 58°
m<MKL = 180 - (58 + 58) (Sum of triangle)
m<MKL = 64°
m<JKM = 180 - m<MKL (linear pair theorem)
m<JKM = 180 - 64 (Substitution)
m<JKM = 116°
∆JKM is also an isosceles triangle with two equal sides. Therefore, it's based angles (x & <J) would also be equal to each other.
Thus:
x = ½(180 - m<JKM)
x = ½(180 - 116) (Substitution)
x = 32°
Answer:
x=24
Step-by-step explanation:
y = x*c
x=2, y=7
2*c=7 => c=7/2
x*7/2 = 84
x = 84*2/7
x = 12*2
x = 24
