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Citrus2011 [14]
3 years ago
12

CAN SOMEONE HELP ME I DON'T GET IT PLEASEE

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

a rise of 20 degrees

Step-by-step explanation:

since it started at -2 degrees, you have to add enough to get out of the negatives.

-2 + 2= 0, then 0+18 to get to the 18°

-2 + 20 = 18

You might be interested in
What is 4/5 ( + ) 1/2 + ( 3/4)
r-ruslan [8.4K]

Answer:

41/20

Step-by-step explanation:

Simplify the following:

4/5 + 1/2 + 3/4

Hint: | Put the fractions in 4/5 + 1/2 + 3/4 over a common denominator.

Put 4/5 + 1/2 + 3/4 over the common denominator 20. 4/5 + 1/2 + 3/4 = (4×4)/20 + 10/20 + (5×3)/20:

(4×4)/20 + 10/20 + (5×3)/20

Hint: | Multiply 4 and 4 together.

4×4 = 16:

16/20 + 10/20 + (5×3)/20

Hint: | Multiply 5 and 3 together.

5×3 = 15:

16/20 + 10/20 + 15/20

Hint: | Add the fractions over a common denominator to a single fraction.

16/20 + 10/20 + 15/20 = (16 + 10 + 15)/20:

(16 + 10 + 15)/20

Hint: | Evaluate 16 + 10 + 15 using long addition.

| 1 |  

| 1 | 6

| 1 | 5

+ | 1 | 0

| 4 | 1:

Answer:  41/20

4 0
3 years ago
Write the doubles plus one fact for 7+7.
Pie

Answer:

7 + 8 = 7 + 7 + 1.

Step-by-step explanation:

We know that, 'double plus one facts' is used to make the addition of numbers easy.

For e.g. we have 8 + 9 = 17. This addition can also be done as 8 + 8 + 1 = 17 i.e. we write first term twice and add 1 to get the result.

Hence, we give the name to this type of addition as 'double plus one'.

Now, we have to use this fact for 7 + 7.

So, we consider 7 + 8 = 15.

Therefore, 7 + 8 can be written as 7 + 7 + 1

Hence, the double plus one facts for 7 + 7 is 7 + 8 = 7 + 7 + 1.

7 0
4 years ago
Read 2 more answers
HELP? PLEASE HELP BY TOMORROW
kherson [118]
A) What is the mean of : 18, 22, 14, 30, 26 x = (18 +22+ 14+ 30+ 26)/5 = 22 (b) What is the sum of the squares of the differences between each data value and the mean: (data point - x)² or (data point - 22)² (18-22)² = 16 (22-22)² = 0 (14-22)² = 64 (30-22)² = 64 (26-22)² = 16 Sum = 16+0+64+64+16 = 160 (c) What is the standard deviation s = √[(∑(x-22)²/(n-1)], where x is the data point, 20 the mean and n =5 √[(∑(x-22)² = 160 and n = 5 (5 data points) then s = 160(5-1) = 160/4 = 40 d) 32, 35, 33, 34, and 36 Rewrite it from smaller to greater: 32, 34, 34, 35 36. We notice that the range is from 32 to 36 is only 4 (36-32), Where as the range of the 1st pumpkins is 30-14 = 16 Since the spread of the 1st one is by far larger than the 2nd, we can conclude that the standard deviation of the 1st is greater than the second

8 0
4 years ago
Simplify the expression. 7t4 ∙ 7t4
Arte-miy333 [17]
7t⁴ * 7t⁴ = 49t⁸

Multiply the coefficients and add the exponents together. 
4 0
3 years ago
Read 2 more answers
Out of the 400 students in a final year in secondary school, 300 are offering biology and 190 are offering chemistry. I) how man
iren2701 [21]

Answer:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

= 160 students

II) how many students are offering at least one biology and chemistry?

= 330 students

Step-by-step explanation:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

Total number of student n ( B ∪ C) = 400

Students offering biology n(B) = 300

Students offering chemistry n(C) = 190

Students not offering biology nor chemistry = 70

Students offering both biology and chemistry n ( B ∩ C) = ??

n ( B ∪ C) - Students neither offering biology nor chemistry = n(B ) + n ( C ) - n ( B ∩ C)

400 - 70 = 300 + 190 - n ( B ∩ C)

330 = 490 - n ( B ∩ C)

n ( B ∩ C) = 490 - 330

n ( B ∩ C) = 160

Therefore, students offering both Biology and Chemistry are 160 students.

II) how many students are offering at least one biology and chemistry?

n(B' ) + n ( C') + n ( B ∩ C)

n(B') = Students offering biology only

= n(B) - n ( B ∩ C)

= 300 - 160 = 140

n(C') = Students offering chemistry only

n(C) - n ( B ∩ C)

= 190 - 160

= 30

(300 - 160) + (190 - 160) + 160

140 + 30 + 160

= 330 students

4 0
3 years ago
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