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Citrus2011 [14]
3 years ago
12

CAN SOMEONE HELP ME I DON'T GET IT PLEASEE

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

a rise of 20 degrees

Step-by-step explanation:

since it started at -2 degrees, you have to add enough to get out of the negatives.

-2 + 2= 0, then 0+18 to get to the 18°

-2 + 20 = 18

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This amount doesn't equal the principal so the problem could be worded incorrectly.


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Help !!!!!! Need to know ASAP
madreJ [45]

Answer:

Multiply by 5

5*2f-5*6g=10f-30g

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2. Find the area. The figure is not drawn to scale.<br> 4 cm<br> 17 cm
BabaBlast [244]
area=base x height so i’m thinking it’s 4x17=68
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Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x<br><br> h(g(f(x)))
alexgriva [62]
Hello here is a solution :
<span>h(g(f(x))) ?

</span>g(f(x))= g(2x+5)=(2x+5)²=(2x)²+2(2x)(5)+5² = 4x²+20x+25
h(g(f(x)))(x) = h(4x²+20x+25) = -2(4x²+20x+25) 
h(g(f(x)))(x) = -8x²-40x-50
8 0
3 years ago
Read 2 more answers
How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)
joja [24]

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}

\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)

You can use the "cover-up" method here to easily solve for a,b,c. It involves fixing a value of x to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.

  • If x=-5, then 94=112a\implies a=\dfrac{47}{56}
  • If x=2, then 10=35b\implies b=\dfrac27
  • If x=\dfrac13, then -\dfrac{50}9=-\dfrac{80}9c\implies c=\dfrac58

So the integral we want to compute is the same as

\displaystyle\frac{47}{56}\int\frac{\mathrm dx}{x+5}+\frac{10}{35}\int\frac{\mathrm dx}{x-2}+\frac58\int\frac{\mathrm dx}{3x-1}

and each integral here is trivial. We end up with

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx=\frac{47}{56}\ln|x+5|+\frac27\ln|x-2|+\frac5{24}\ln|3x-1|+C

which can be condensed as

\ln\left|(x+5)^{47/56}(x-2)^{2/7}(3x-1)^{5/24}\right|+C

7 0
3 years ago
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