All categories

3 years ago

Simplify the expression: (26 - 3)(-6) =

Mathematics

1 answer:

Makovka662 [10]3 years ago

7 0

Answer & Step-by-step explanation:

(26 - 3)(-6)

Subtract 3 from 26 first.

(23)(-6)

Now multiply 23 by -6.

-138

So, (26 - 3)(-6) equals -138.

You might be interested in

Help please ! Please

gizmo_the_mogwai [7]

Answer:

15, 8, 25 The teacher payed 0.40 per book.

Step-by-step explanation:

4/10 = 2/5 Simplify the 4/10 to find the unit rate.

15: 2/5 = 6/x Set up your proportion.

2x =30 Cross multiply

/2 /2 Divide both sides by 2 to isolate x

x =15

8: 2/5 = x/20 Set up proportion

40 =5x Cross multiply

/5 /5 Divide both sides by 5 to isolate x

8 =x

25: 2/5 = 10/x Set up proportion

2x =50 Cross multiply

/2 /2 Divide both sides by 2 to isolate x

x =25

Graph: y=mx+b To graph, you will need to use y=mx+b format

y= 2/5 x+2 2/5 is your unit rate. Your rate changes every 2 books bought. To graph, start at (0,2) and go up 2 and to the right 5, plot. Continue moving up 2 and to the right 5 to graph.

The teacher payed 0.40 per book because 2/5 simplifies to 0.40.

8 0

3 years ago

The volume of a volleyball is about 288 cubic inches. what is the radius of the volleyball, to the nearest tenth of an inch? use

Len [333]

Answer:

The radius of the volleyball is 8.3 inches

Step-by-step explanation:

Given

$r = \sqrt{\frac{3v}{4\pi}}$

$v = 288$

Required

Determine the value of r

To do this, we simply substitute 288 for v and 3.14 for π in the given equation.

This gives

$r = \sqrt{\frac{3v}{4\pi}}$

$r = \sqrt{\frac{3 * 288}{4 * 3.14}}$

$r = \sqrt{\frac{864}{12.56}}$

$r = \sqrt{68.7898089172}$

$r = 8.29396219651$

$r = 8.3\ inch$ (Approximated)

Hence;

The radius of the volleyball is 8.3 inches

3 0

3 years ago

Read 2 more answers

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, for the y direction, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$