The path consists of 4 line segments. Each line segment is the hypotenuse of a different right triangle.
length of line segment AB =
length of line segment BC = 
length of line segment CD = 
length of line segment DE 
The total length of the spider's path is about 20.13 cm.
2000(1.0625)dave vs sam 2000(1.05)+30
2125 dave vs. sam 2,100+30
2125 dave vs. sam 2130
dave is correct, because it costs five dollars less in massachusetts than in Maine
Answer:
1
Step-by-step explanation:
Using the trigonometric identities
• csc x = 
• tan x = 
cos x ×
× 
Cancel sin x and cos x on the numerator/ denominator leaving
1
Answer:
(11a+b+1)
Step-by-step explanation:
(1): "a2" was replaced by "a^2". 2 more similar replacement(s). (((((3•(a2))•b)+5ab)-4ab)+(a•(b2)))+(23a2•b) ((((3a2 • b) + 5ab) - 4ab) + ab2) + 23a2b Pull out like factors :
11a2b + ab2 + ab = ab • (11a + b + 1)