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grigory [225]
3 years ago
8

Look at the expression below. (Math Problem Attached)

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

its 6x ,6 and 3(y+2)

Step-by-step explanation:

My ArT hErE yOu Go

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Draco Malfoy or the Weasley twins?
tekilochka [14]

Answer:

DRACO MALFOY FOR SURE

Step-by-step explanation:

7 0
2 years ago
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Y + 0.5xy = x + 2; x = 1<br> How do you solve for y
vfiekz [6]

Step-by-step explanation:

replace the value of x with 1

y + 0.5 × 1 × y = 1 + 2

do the maths

y + 0.5y = 3

here the value of y is equal to 1. same goes for x, if we have no given value for them.

1.5y = 3

y = 3/1.5

y = 2

6 0
3 years ago
A movie theater determines its profit, in dollars, using the expression 10n - 1000, where n is the number of tickets sold.
Alja [10]

Answer:

E

600

Step-by-step explanation:

10n - 1000 = 5000

10n = 6000

n = 600

HOPE THIS HELPS

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7 0
3 years ago
Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.
BabaBlast [244]

Answer:

C

Step-by-step explanation:

We want to solve the equation:

x^2+2x+7=0

Using the quadratic formula. The quadratic formula is given by:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 2, and <em>c</em> = 7.

Substitute:

\displaystyle x=\frac{-(2)\pm\sqrt{(2)^2-4(1)(7)}}{2(1)}

Evaluate:

\displaystyle x=\frac{-2\pm\sqrt{-24}}{2}

Simplify the square root:

\sqrt{-24}=\sqrt{4\cdot 6\cdot -1}=\sqrt{4}\cdot\sqrt{6}\cdot\sqrt{-1}=2i\sqrt{6}

Hence:

\displaystyle x=\frac{-2\pm2i\sqrt{6}}{2}

Simplify:

\displaystyle x=-1\pm i\sqrt{6}

Hence, our solutions are:

\displaystyle x=\left\{-1+i\sqrt{6}, -1-i\sqrt{6}\right\}

Our answer is C.

3 0
3 years ago
Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a parti
Marizza181 [45]

Answer:

a) X^ = 70 GPa , s = 0.4 GPa

b) X^ = 70 GPa , s = 0.2 GPa

c) n = 64 .. part b

Step-by-step explanation:

Solution:-

- A sample ( n ) was taken from aluminum alloy sheets of a particular type the distribution parameters are given below:

                      Mean ( u ) = 70 GPa

                      Standard deviation ( σ ) = 1.6 GPa

a)

- We take a sample size of n = 16. The random variable X denotes the distribution of the sample obtained.

- We will estimate the parameters of the sample distribution X.

- The point estimate method tells us that the population mean ( u ) is assumed as the sample mean ( X^ ).

                    Sample Mean ( X^ ) = u = 70 GPa

- The sample standard deviation ( s ) for the given sample with known population standard deviation ( σ ) is given by:

                   sample standard deviation ( s ) = σ / √n

                   sample standard deviation ( s ) = 1.6 / √16

                   sample standard deviation ( s ) = 0.4 GPa

b)

Repeat the above calculations for sample size n =  64.

- We will estimate the parameters of the sample distribution X.

- The point estimate method tells us that the population mean ( u ) is assumed as the sample mean ( X^ ).

                    Sample Mean ( X^ ) = u = 70 GPa

- The sample standard deviation ( s ) for the given sample with known population standard deviation ( σ ) is given by:

                   sample standard deviation ( s ) = σ / √n

                   sample standard deviation ( s ) = 1.6 / √64

                   sample standard deviation ( s ) = 0.2 GPa

c)

- The standard deviation ( s ) gives us the uncertainty of mean ( X^ ). How spread apart/close are the data points from the mean.

- We see that standard deviation ( s ) has an inverse relation to the sample size ( n ):

                   sample standard deviation ( s ) = σ / √n

- So with increasing sample size the there is a decreased variability in the sample distribution of ( X ).

Answer: The sample size n = 64 used in part b would give us lesser variability of sample distribution of X as compared to sample size n = 16 used in part a. Hence, X is more likely to be within 1 GPa of the mean in part (b). This is due to the decreased variability

4 0
3 years ago
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