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mr_godi [17]
3 years ago
15

An example of a satistical question?

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0

Answer: Like for example, Do dogs run faster than cats? Or, In general will I use less gas driving at 55mph than 70mph? ..Is that helpful enough? Let me know

Step-by-step explanation:

docker41 [41]3 years ago
3 0

How much do the animals at the Fancy Farm weigh?

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Find the value of x
anastassius [24]
It would be 67 because its the same decrease as the other.


4 0
4 years ago
Find the circumference of a circle with a diameter of 18 in
brilliants [131]

Here is your answer

\bold{56.52 in}

REASON:

Diameter, d= 18 in

So,

Circumference = pi×d

= 3.14×18 in

= 56.52 in

HOPE IT IS USEFUL

5 0
3 years ago
(1 point) Some airlines have restrictions on the size of items of luggage that passengers are allowed to take with them. Suppose
Kamila [148]
Here L = W, but H can be different.
 
The sum L+H+W  must be less than or equal to 192 cm.  

We can solve L + H + W = 192 for H:  H = 192 - W - L.  Remembering that W = L,   the formula for H becomes 192 - 2W.

The formula for volume would be V = L*W*H.

This becomes V = W*W*H, or  V = W^2*(192-2W)

Multiplying this out:  V = w^2*192 - 2W^3

Two ways of determining W:

1) graph V = 192W^2 - 2W^3 and determine the value of W at which V is at a max with the constraint W + L + H is equal to or smaller than 192.

2) Differentiate V with respect to W and set the result equal to zero:

384W - 6W^2 = 0.  Solving for W:  W(384 - 6W) = 0.

W = 0 is trivial, so just solve 384 - 6W = 0 for W:  6W = 384, and W = 64.

The width is 64 cm, the length is 64 cm also, and the height is (192-2W) cm, or 64 cm.

These dimensions produce the max volume.
4 0
3 years ago
The table and graph both represent the same relationship. Which
nordsb [41]

Answer:

We conclude that all the points of the table satisfy the equation y = x²

Hence, the option containing the equation y =  x² is true.

The graph of y =  x² is also attached below.

Step-by-step explanation:

Given the table

x             y

-2           4

-1             1

0            0

1             1

2            4

Let us substitute the x-values of the table in the equation

y = x²

plun in x = -2

y = (-2)² = 4

so the point (2, 4) lies on the graph of y =  x²

y = x²

plun in x = -1

y = (-1)² = 1

so the point (-1, 1) lies on the graph of y =  x²

y = x²

plun in x = 0

y = (0)² = 0

so the point (0, 0) lies on the graph of y =  x²

y = x²

plun in x = 1

y = (1)² = 1

so the point (1, 1) lies on the graph of y =  x²

y = x²

plun in x = 2

y = (2)² = 4

so the point (2, 4) lies on the graph of y =  x²

Therefore, we conclude from the above calculations that all the points of the table satisfy the equation y = x²

Hence, the option containing the equation y =  x² is true.

The graph of y =  x² is also attached below.

5 0
3 years ago
A cuboid is measuring 3cm by 5cm by 2cm is enlarged by a ratio of 2:1.
Svetlanka [38]

Step-by-step explanation:

a) i) original cuboid = 3×5×2 = 30 cm³......(i)

ii) ratio : 3×2 = 6cm (width), 5×2 = 10 cm (length),

2×2 = 4 cm (height).

enlarged cuboid = 6×10×4 = 240 cm³....(ii)

b) ratio = 240cm³/30cm³ = 8:1.

hope this helps you.

7 0
3 years ago
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