4 x’s for 1/4
2 x’s for 2/4
1 x for 3/4
2 x’s for 1
No. We claim that
and use algebra to prove the statement.
Let
. Multiply this by ten to get
. Subtract the initial equation to give
and divide by
to see that
. Substituting into the original equation gives
, proving the desired statement.
Answer:
Step-by-step explanation:
Let
h(t) ---> the height of an object in meters
t ----> the time in seconds
we have
For t=6 sec
substitute in the quadratic equation the value of t and solve for h
Answers:1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:1) Value of the functions as x increases.Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1,
the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.While in the graph you see that the function
q has a horizontal asymptote that shows that the
limit of q (x) when x → ∞ is - 4.Then, the first answer is that
as x increases the value of p(x) approaches a number that is greater than q (x).2) y - intercepts.i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2ii) The y-intercept of q(x) is read in the
graph. It is - 3.
Then the answer is that
the y-intercept of the function p is greater than the y-intercept of the function q.
There is unlimited possibility’s to that question