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Tcecarenko [31]
3 years ago
12

Need math help please get back to me soon

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

Option C.

Step-by-step explanation:

By definition, a function f(x) is even if f(-x) =  f(x).

We know by definition that the function sin(x) is odd and the function cos(x) is even.

With this information we can analyze each function and find out which is even.

A. The first function is not even because 5sin(x) is an odd function.

B. The second function is not even because 2tan(x) is not an even function.

C. The third function is even, because -cos(x) and 3cos^2(3x) are even functions.

f(-x) = 3cos^2(3(-x)) - cos(-x) = 3cos^2(3(x)) - cos(x) = f(x)

D. The fourth function is not even because csc(x) is not an even function.

The correct answer is the option C.

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What is the value of x? x = 23   x = 35 x = 58 x = 93
Akimi4 [234]

we know that

m∠SQR+x=180 -------> by supplementary angles

so

m∠SQR=180-x

The sum of the internal angles of a triangle is equal to 180 degrees

m∠SQR+m∠QSR+m∠SRQ=180

substitute the values in the formula

m∠SQR+35+58=180

m∠SQR=87 degrees

<u>Find the value of x</u>

m∠SQR=180-x

x=180-m∠SQR

x=180-87

x=93 degrees

therefore

<u>the answer is</u>

the value of x is 93 degrees

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3 years ago
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Evaluate the expression 4+−4√2+−1√ and write the result in the form a+bi.
castortr0y [4]

In the expression, the real number a equals 12 and the real number b equals -16.

<h3>How to explain the information?</h3>

It should be noted that the expression given is:

= (4 - 2i)²

Therefore, we need to expand the expression. This will be:

= (4 - 2i)(4 - 2i)

= 16 -8i -8i + 4i²

= 16 -16i +4i²

Substitute -1 for i²

= 16 - 16i + 4(-1)

= 16 - 16i - 4

= 12 - 16i

Therefore, the value of the expression is 12 - 16i.

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brainly.com/question/723406

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Evaluate the expression ( 4 − 2 i )² and write the result in the form a + b i.

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2 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

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The 200$ camera was on sale 15% off what was the price
Flauer [41]
Answer: $170
15% off 100 is $15 x2 is 30
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nikdorinn [45]

Answer:

Why  do you feel sad

Step-by-step explanation:

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