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3 years ago

One over four (4x + 15) = 24

Mathematics

2 answers:

never [62]3 years ago

7 0

The answer is x=20 1/4

kiruha [24]3 years ago

3 0

Answer:

x = 20 1/4

Step-by-step explanation:

1/4 (4x + 15) = 24

x + 3 3/4 = 24

x = 20 1/4

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Decrease £280 by 73%

bekas [8.4K]

280 x (1-0.73)
=280 x 0.37
= £103.60

£280 decreased by 73% is £280 multiplied by 37%.

If this answer has helped you, please make sure to leave a Thank You.

4 0

3 years ago

Prove that 5^7+5^6 is divisible by 6.

Valentin [98]

Answer:

5^7+5^6 = 93750

93750/6 = 15625

Hence 5^7+5^6 is divisible by 6.

Step-by-step explanation:

3 0

4 years ago

7 times what equals 1?

Arturiano [62]

For this case, the first thing we must do is define a variable.
We have then:
x: unknown number
Doing the multiplication we have:
$(7) (x) = 1
$
From here, we clear the value of x.
We have then:
$x = \frac{1}{7} 
$
Therefore, we have:
$(7) ( \frac{1}{7} ) = 1
$
Answer:
7 times 1/7 equals 1

4 0

3 years ago

Read 2 more answers

Using the number line below to compare the list of numbers. Place the numbers in increasing order.

Ivanshal [37]

Answer:

-2/5

-1.5

1 4/5

Step-by-step explanation:

The higher the negatice number, the lower it is. Hope this helps:)

4 0

2 years ago

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

3 years ago