Question

Remember that in Cynthia's physics class, she must turn in four lab reports. For each report, she earns extra credit if her percent error is less than 5%. For her second lab report, she calculated the height of a building four times. She got the following four heights. 6.8 7.5 8.1 7.8 The true height of the building is 7 m. What was Cynthia's percent error? Remember: Take the average of the three measurements before calculating the percent error.

Answer 1

Answer:

7.86% error

Step-by-step explanation:

First, we need to average the four heights she got. We do this by adding them all together and then dividing the sum by 4:

$\frac{6.8+7.5+8.1+7.8}{4} =\frac{30.2}{4} =7.55$

So, the average height is 7.55. Now, to find percent error, the formula is:

( | accepted value - experimental value | ) / (accepted value)

(Note that the | | in the numerator denotes absolute value)

Here, the accepted value is 7, while the experimental value is 7.55. So, we plug in the values: $\frac{|7-7.55|}{7} =\frac{|-0.55|}{7} =\frac{0.55}{7} =0.0786$

Now, to turn this into a percent, we multiply 0.0786 by 100: 0.0786 * 100 = 7.86%.

Thus, the answer is 7.86% error.

Hope this helps!

Answer 2

Answer:

I honestly don’t know I’m sorry that no one helped...

Step-by-step explanation: