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mariarad [96]
3 years ago
8

What times what equals 72

Mathematics
2 answers:
ella [17]3 years ago
4 0
Your answer is 36 times 2
liq [111]3 years ago
3 0
8*9=72.
Hope this helped :)

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Answer:

Commutative Property of Multiplication.

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Sarah said that 0.00001 is bigger than 0.001 because the first number has more digits to the right of the decimal point. Is Sara
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No, she is wrong. 0.00001 has 4 zeros in front of the one and behind the decimal, making it 1/100000 or 1/10^5. For 0.001, there are 2 zeros in front, making it 1/1000 or 1/10^3. Since a number gets smaller as the denominator gets larger, and 10^5>10^3, 1/10^5<1/10^3
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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
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Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

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C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

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Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

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r = \frac{\ln{0.5}}{4}

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So for the husband

C(t) = 110e^{-0.1733t}

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7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

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7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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