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olya-2409 [2.1K]
1 year ago
12

Solve the simultaneous equation 2x + 3y = 7 3x + 2y = 8​

Mathematics
1 answer:
Verdich [7]1 year ago
6 0

Answer:

(2, 1 )

Step-by-step explanation:

2x + 3y = 7 → (1)

3x + 2y = 8 → (2)

multiplying (1) by 3 and (2) by - 2 and adding will eliminate x

6x + 9y = 21 → (3)

- 6x - 4y = - 16 → (4)

add (3) and (4) term by term to eliminate x

0 + 5y = 5

5y = 5 ( divide both sides by 5 )

y = 1

substitute y = 1 into either of the 2 equations and solve for x

substituting into (1)

2x + 3(1) = 7

2x + 3 = 7 ( subtract 3 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 1 )

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Simplify 3 - (4x - 5) + 6.<br> A) 12x + 21 <br> B) 4x + 14 <br> C) 4x + 4 <br> D) -4x + 14
stepladder [879]

Answer:

D) -4x+14

Step-by-step explanation:

We are given with the expression

3 - (4x - 5) + 6

Here we are going to open the bracket at first step

as we have a negative sign in front of bracket the signs of the terms inside brackets will be reversed

3-4x+5+6

now we bring the like terms together

3+5+6 - 4x

Here 3, 5, 6 all are constant and hence like

14-4x

or

3 - (4x - 5) + 6= -4x+14

Hence our answer is -4x+14

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