What is the hypotenuse of a triangle with a base of 11cm and height of 9cm
2 answers:
A^2+b^2=c^2
11^2+9^2=c^2
121+81=c^2
202=c^2
square root(202)
14.21=c
A² + b² = c²
11² + 9² = c²
121 + 81 = c²
202 = c²
√202 = c
14.2126704035518955 = c
Rounded 14.2126704035518955 ≈ 14.2
I hope this helps. (:
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