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katrin [286]
2 years ago
8

(x - 4)(x + 2) in factored form, use the FOIL method to turn it into standard form

Mathematics
1 answer:
Verdich [7]2 years ago
7 0

Answer:

{x}^{2}  - 2x - 8

Step-by-step explanation:

(X - 4)(X+2)

( {x}^{2}  + 2x - 4x - 8) \\ ( {x}^{2}  - 2x - 8)

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Perform the indicated operations:
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B. x+1 / x+9

Step-by-step explanation:

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Help me for brainlist
igor_vitrenko [27]

Answer:

1. g. $0.10 per square inch

2. c. $0.08 per square inch

3. f. $10

4. m. $8

5. h. 79 in²

6. j. 113 in²

Step-by-step explanation:

1. A = πr²

   r = diameter ÷ 2 = 10 ÷ 2 = 5

   A = π(5)² = 25π in² ≈ 78.53981

   $8.00/25π = $0.10 per square inch

2. A = πr²

   r = diameter ÷ 2 = 12 ÷ 2 = 6

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3. information/answer was provided

4. information/answer was provided

5. A = πr²

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   A = π(5)² = 25π in² ≈ 79 in²

6. A = πr²

   r = diameter ÷ 2 = 12 ÷ 2 = 6

   A = π(6)² = 36π in² ≈ 113 in²

5 0
2 years ago
if i need to pay 154 dollars for something but get paid 10 dollars every week how many weeks would i have to wait
AveGali [126]

154/10=15.4. Then apply greatest integer function (smallest integer larger than that number) to get 16.


3 0
3 years ago
Two trains are 400 miles apart, and their speeds differ by 10 mph. They travel toward each other and meet in 4 hours. Find the s
Katen [24]
So.. the two trains, are 400 miles apart, their speeds differ by 10, so one train is faster than the other.. .let's say   train A is faster than train B, by 10mph

so if train A has a speed rate of "r", then B has a rate of "r - 10"

after train A has beeng running for 4hrs, it has travelled a distance "d"

train B has travelled also for 4hrs, they're both 400 miles apart, and travelling towards each other, so the total distance travelled by both is 400miles

so after 4hours B has travelled the slack from 400 and "d", namely 400 - d

recall your d = rt --> distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{Train A}&d&r&4\\
\textit{Train B}&400-d&r-10&4
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
\boxed{d}=4r\\
400-d=(r-10)4\\
----------\\
400-\boxed{4r}=(r-10)4
\end{cases}

solve for "r", to find the speed of the faster train A

what's the speed of B? well, B's rate is r - 10
4 0
3 years ago
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