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4 years ago

Raidius 8 and hight 10 what is the volume?

Mathematics

1 answer:

aev [14]3 years ago

7 0

Answer:

V≈2010.62

Step-by-step explanation:

The volume of a cylinder is V=πr^2h so plug in 8 for r and 10 for h

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What is the radius of a semi circle when the area is 20cm

vazorg [7]

hello :
the area of the circle is : 40 cm²
40 = <span>πr²
r² = 40/(3.14 )
r² = 12.73 cm</span>

6 0

3 years ago

PLEASE HELP ME AND THANK THIS QUESTION IS 100 POINTS

kolezko [41]

First pic

a. ΔMNK ≅ ΔRTP

b. TR ≅ NM

c. x = 7

3x - 1 = 20

3x = 20 + 1

3x = 21

x = 21 ÷ 3

x = 7

Second pic

SAS (Side-Angle-Side congruence)

SSS (Side-Side-Side)

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3 years ago

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2x + 4y = 30 x = y - 6

Rufina [12.5K]

Answer:

x = 1 , y = 7

Step-by-step explanation:

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3 years ago

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Mr. Smith collected 200 eggs from his chickens on Saturday. When he sorted the eggs by their sizes, he found out tha 60% of the

Bond [772]

Answer: 120

Step-by-step explanation:

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2 years ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

3 years ago