All categories

3 years ago

Tyrone likes to snack on his big bag of candy. He takes

Mathematics

2 answers:

cestrela7 [59]3 years ago

4 0

Dhjdjdjdjdjdjdjduddj google it

Alekssandra [29.7K]3 years ago

3 0

Answer:

c=150-8s

Step-by-step explanation:

I did the same khan lesson lol trust me it is right.

You might be interested in

One serving of a fruit punch recipe serves 16 people. ( number of servings, number of people served .) which of the following li

Inessa05 [86]

It would be list f. Each serving(1)serves16 so 2 servings serve 32 and so on.

8 0

3 years ago

Triangle ABC has vertices A(-2,0), B(2,5), C(3, 1). The reflection of the image of triangle ABC is triangle A'B'C' with vertices

geniusboy [140]

Answer: Reflection about x-axis

Step-by-step explanation:

Given

Initially, vertices are $A(-2,0), B(2,5),C(3,1)$

After reflection they become $A(-2,0),B(2,-5),C(3,-1)$

It is clear that the x coordinate remains unchanged and the y coordinate changes its sign. It occurs when reflection is done about the x-axis.

For example, when (a,b) is reflected about the x-axis, it becomes (a,-b).

So, here reflection is being done about the x-axis.

4 0

3 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago

Identify the slope of the line for the equation y = −9x − 7

Alex Ar [27]

Answer:

the slope is -9x

Step-by-step explanation:

whatever has x next to it is the slope

8 0

3 years ago

Read 2 more answers

A total of 300 pine and maple trees will be planted in a park. There will be 2 pine trees planted for every 3 maple trees plante

mars1129 [50]

Answer:

120

Step-by-step explanation:

2 of every 5 trees are pine trees.

2/5 · 300 = 120

120 pine trees are going to be planted in the park.

5 0

3 years ago