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kramer
2 years ago
14

10. A In the adjoining Figure, ab is perpendicular to bc and ed is to cd while bc=cd . prove i) triangle abc is corresponding to

triangle edc
ii)ab = cd

​

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>

1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)

2) Angles ABC and CDE are right angles (perpendicular lines form right angles)

3) Angles ABC and CDE are equal (all right angles are equal)

4) Angles ACB and DCE are equal (vertical angles are equal)

5) Triangles ABC and EDC are congruent (ASA)

<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>

6) AB = DE (corresponding parts of congruent triangles are equal)

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Find the midpoint of the line segment joining the points (-2, -1) and (-8,12).
SCORPION-xisa [38]

x¹ = -2 x² = -8

y¹ = -1 y² = 12

Using midpoint formula,

M = ( x¹ + x²/2 ,y¹ + ý²/2)

or,M ={ -2+(-8)/2 , (-1) +12/2}

or, =( -10/2 , 11/2)

:M = ( -5 , 11/2)

6 0
2 years ago
A farmer leans a 12-ft ladder against a barn. The base of the ladder is 3 ft from the barn. To the nearest tenth, how high on th
DENIUS [597]

The barn, the ground, and the ladder form a right triangle. If we represent the height on the barn by y, then the Pythagorean theorem tells us

... hypotenuse² = (side1)² + (side2)²

... (12 ft)² = (3 ft)² + y² . . . . . . . . . . . . fill in given information

... 144 ft² - 9 ft² = y² = 135 ft² . . . . . .subtract (3 ft)²

... y = 3√15 ft ≈ 11.6 ft . . . . . . . . . . . take the square root

The ladder reaches 11.6 feet high on the barn.

4 0
3 years ago
Read 2 more answers
GIVING BRAINIEST IF CORRECT!!<br><br> Factor x^4 - 16 completely
ioda

Answer:

(x^2 + 4)(x + 2)(x - 2)

Step-by-step explanation:

Hello!

We can use the difference of square method.

<h2>Difference Of Squares (DOS)</h2>

The formula for the DOS is (a + b)(a - b) = a^2 - b^2

It is a simple way to factor polynomials.

The criteria:

  • Has to begin and end with a perfect square
  • The operation has to be subtraction

<h3>Factor:</h3>
  • x^4 - 16

Begins with a perfect square (x² * x²) and ends with a perfect square (4 * 4)

  • (x^2 + 4)(x^2 - 4)

Warning! Watch out, there may be another DOS!

x^2 - 4 is another DOS

  • (x^2 + 4)(x + 2)(x - 2)

The x² + 4 is not a DOS because the operation is addition.

The final factored form is (x^2 + 4)(x + 2)(x - 2)

8 0
2 years ago
A triangle has side lengths of (x-6), (x+2) and (x-9). Find the perimeter of the triangle
Setler [38]

Answer:

3x - 13

Step-by-step explanation:

The perimeter is just the distance around the triangle. We have all three sides, so we can just add them together to get the total distance.

(x-6) + (x+2) + (x-9)

Group:

x + x + x - 6 + 2 - 9

3x - 13

8 0
3 years ago
Please answer this question!
Aleks [24]
406 divided by 140 makes 2.9 multiply that 100 and you arrive at 290%. Hope this helps!
8 0
3 years ago
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