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kramer
2 years ago
14

10. A In the adjoining Figure, ab is perpendicular to bc and ed is to cd while bc=cd . prove i) triangle abc is corresponding to

triangle edc
ii)ab = cd

​

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>

1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)

2) Angles ABC and CDE are right angles (perpendicular lines form right angles)

3) Angles ABC and CDE are equal (all right angles are equal)

4) Angles ACB and DCE are equal (vertical angles are equal)

5) Triangles ABC and EDC are congruent (ASA)

<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>

6) AB = DE (corresponding parts of congruent triangles are equal)

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The first term of an arithmetic sequence is -5, and the tenth term is 13.
Leokris [45]

Answer:

Step-by-step explanation:

Let d be the common difference.

a₁₀ = a₁ + (10-1)d

13 = -5 + 9d

d = 2

5 0
2 years ago
The next stop on the road trip is the zoo! jacob goes to find his favorite animal, the giraffe. jacob wonders how tall the talle
lapo4ka [179]
1 foot = 12 inches
Height of Jacob = 5 feet 6 inches = 5 *12 + 6 = 66 inches
Jacob's <span>shadow = 3 feet = 36 inches

</span>giraffe's shadow = <span>5 feet 9 inches = 5 * 12 + 9 = 69 inches

</span><span>by the ratio and proportion

∴ </span>Height of Jacob/Jacob's shadow = Height of giraffe/giraffe's shadow

∴ 66/36 = Height of giraffe/69

∴ Height of giraffe = 69 * 66/36 = 126.5 inches = 10 feet 6.5 inches
3 0
3 years ago
From his house, Tom rides his bike 5 kilometers east to the store. He then rides his bike 2 kilometers west to his friends house
mario62 [17]

Answer:

3 km

Step-by-step explanation:

He starts by going 5 km east, then he turns around and goes 2 km west. So he is now 3 km from his house.

7 0
2 years ago
How do you solve this
Nezavi [6.7K]

Answer:

this is how u solve this

Step-by-step explanation:


5 0
3 years ago
1. Find the measurement of angle J.<br><br> 2. (5x - 13) (3x + 17)
Alex Ar [27]

Answer:

Q1. x= 18, y=59

Q2. m∠J= 56°

Step-by-step explanation:

Q1. (3x +5)°= y° (base ∠s of isos. △)

y= 3x +5 -----(1)

(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)

3x +5 +y +4x -10= 180

7x +y -5= 180

7x +y= 180 +5

7x +y= 185 -----(2)

Substitute (1) into (2):

7x +3x +5= 185

10x= 185 -5

10x= 180

x= 180 ÷10

x= 18

Substitute x= 18 into (1):

y= 3(18) +5

y= 59

Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)

5x -13= 3x +17

5x -3x= 17 +13

2x= 30

x= 30 ÷2

x= 15

∠LKJ

= 3(15) +17

= 62°

∠KLJ= 62° (base ∠s of isos. △)

m∠J

= 180° -62° -62° (∠ sum of △JKL)

= 56°

8 0
3 years ago
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