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Nady [450]
3 years ago
6

Consider a circle whose size can vary. Let r represent the radius of the circle (in cm) and let C represent the circumference of

the circle (in cm). Suppose the function f determines the circumference of the circle in cm, C , given its radius length in cm, r .'
a. Write a function formula for f.

b. What does f(12) represent in this context? Select all that apply.

i. The radius (in cm) of a circle whose circumference is 12 cm.
ii. A circle with a radius of 12 cm.
iii. The circumference (in cm) of a circle whose radius is 12 cm.
iv. A circle with a circumference of 12 cm.

c. If f(a) 12, what does a represent in this context? Select all that apply.
i. The circumference (in cm) of a circle whose radius is 12 cm.
ii. The radius (in cm) of a circle whose circumference is 12 cm.
iii. A circle with a circumference of 12 cm.
iv. A circle with a radius of 12 crm

d. What values can r assume in this context?
e. What values can f(r) assume in this context?
Mathematics
1 answer:
lora16 [44]3 years ago
8 0

Answer and Step by Step Explanation

a) f(r) = 2πr

The question only asks for the expression for circumference in which the value of the radius can always be plugged in and a circumference obtained. And this, from basic geometry is 2πr.

b) Option (iii) is correct.

f(12) represents the circumference (in cm) of a circle whose radius is 12 cm.

A radius of r = 12 cm was plugged into the circumference equation and f(12) is the answer obtained.

c) Option (ii) is correct.

In the context f(a) = 12, a represents the radius (in cm) of a circle whose circumference is 12 cm

A radius of r = a cm was plugged into the circumference equation and 12 is the answer for circumference obtained.

d) In this context, the radius can take on values of every positive real number.

This is because simply, the radius of a circle is defined as a straight line from the center of a circle to the circumference of a circle.

Although, generally, a radius can take on virtually any real or imaginary number because more technically, a circle is the locus of all points equidistant from a central point. And this opens the scope of the radius. The general equation of a circle with centre (a,b) and radius, r is given as

(x - a)² + (y - b)² = r²

The square on the r, gives it the power to have such a wide range of values.

e) In this context, the circumference can take on values of every positive real number.

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It is 16 I’ve done this question before
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3 years ago
Solve for 19= -3a -5
Vesnalui [34]

Answer:

a = -8

Step-by-step explanation:

19 = -3a - 5

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6 0
3 years ago
Read 2 more answers
Given f(x) = x² - 10x + 22, what is the range of f?
adoni [48]

Answer:

[-3, ∞)

Step-by-step explanation:

There are many ways to find the range but I will use the method I find the easiest.

First, find the derivative of the function.

f(x) = x² - 10x + 22

f'(x) = 2x - 10

Once you find the derivative, set the derivative equal to 0.

2x - 10 = 0

Solve for x.

2x = 10

x = 5

Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.

f(x) = x² - 10x + 22

f(5) = 5² - 10(5) + 22

      = 25 - 50 +22

      = -3

Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.

This means the range is : [-3, ∞)

Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).

Hope this helped!

6 0
2 years ago
-25 Points-
Elden [556K]

Answer:

(x+1)^2+(y+1)^2=13

Step-by-step explanation:

Equation of a circle: (x – h)^2 + (y – k)^2 = r^2

center: (-1, -1)

radius: sqrt(6^2+4^2)/2=sqrt(52)/2=2sqrt(13)/2=sqrt(13)

Substitute those values in to get

(x+1)^2+(y+1)^2=13

7 0
3 years ago
Can someone pls help me<br> Pls
lora16 [44]

Answer:

help u with what? Say what u need

5 0
2 years ago
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