Step-by-step explanation:
f(x)=x^2+x
so
f(x-1) = (x - 1) ^ 2 + (x - 1)
= x^2 - 2x + 1 + x - 1
= x^2 - 3x
and
f(x+1) = (x + 1) ^ 2 + (x + 1)
= x^2 + 2x + 1 + x + 1
= x^2 + 3x + 2
now
f(x-1) + f(x+1) = 6
x^2 - 3x + x^2 + 3x + 2 = 6
2x^2 = 4
X = √2
brainliest pls took long enough to solve
Assuming n starts at 0, the fourth term would be n=3. c(3)=-7+6(2)=12-7=5
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
(x - 4)² + y² = 16
Step 02:
polar form:
x = r cos (θ)
y = r sin (θ)
(r cos (θ) - 4 )² + (r sin (θ))² = 16
(r cos θ - 4)² + r² sin² θ = 16
r (r - 8 cos (θ)) = 0
r = 8 cos θ
The answer is:
r = 8 cos θ
<u>Answer:</u>
<u>(A) Right </u>
<u>(B) Obtuse </u>
<u>(C) Equilateral </u>
<u>(D) Isosceles</u>
<u>A right triangle must contain a right angle and two acute angles.</u>
<u>An obtuse triangle must contain an obtuse angle and two acute angles.</u>
<u>An equilateral triangle must be 60 degrees in every corner, and thus there are 2+ acute angles.</u>
<u>An isosceles triangle can have two angles that are 30 degrees (thus two acute), and a 120 degree angle.</u>
