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Amiraneli [1.4K]

3 years ago

13

A grey squirrel population was introduced in a certain county of Great Britain 35 years ago. Biologists observe that the populat

ion doubles every 7 years, and now the population is 60,000.
(a) What was the initial size of the squirrel population?

2 answers:

zheka24 [161]3 years ago

6 0

If this occurred over a span of 35 years and the population doubles every 7 years, we can divide 35 by 7 to find how many times the population has doubled, which would be 5 times. If we divide 60,000 by 2 (or multiply by 1/2) 5 times, you would get the answer, which would be 1,875.

NISA [10]3 years ago

6 0

it is 5 periods - 7 years each, 5*7 =35 years

120000-->60000-->30000-->15000-->7500-->3750

Initial population was = 3750 squirrels

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Answer:

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Step-by-step explanation:

For the first equation, let's use $\frac{-a}{b} =\frac{a}{-b} =-\frac{a}{b}$ to right a new fraction.

Step 1- Reduce the fraction with 4.

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Step 1- Convert the mixed number to an improper fraction.

$\frac{6\frac{3}{9} }{\frac{11}{5} } = \frac{\frac{57}{9} }{\frac{11}{5} }$

Step 2- Simplify the complex fraction.

$\frac{\frac{57}{9} }{\frac{11}{5} } = \frac{95}{33}$

An alternative form for this fraction is $2\frac{29}{33} or 2.87$ .

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To divide by a fraction, multiply by the reciprocal of that fraction.

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Multiply the numbers.

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Alternative form of this fraction is $4\frac{2}{7}$ or 4.285714.

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