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vredina [299]
3 years ago
12

Suppose the coefficient matrix of a system of linear equations has a pivot position in every row. Explain why the system is cons

istent?
Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

If in each row of the supposed coefficient matrix, there is a pivot position. Therefore, it is true that the bottom row of the coefficient matrix also has a pivot position. As a result, there will not be space for the augmented column to have a. Thus, we say the system is consistent.

Step-by-step explanation:

In the problem, we have a coefficient matrix comprising linear equations. If in each row of the supposed coefficient matrix, there is a pivot position. Therefore, it is true that the bottom row of the coefficient matrix also has a pivot position. As a result, there will not be space for the augmented column to have a. Thus, we say the system is consistent based on the theorem.

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kvv77 [185]

Answer:

1 solution

Step-by-step explanation:

6 0
3 years ago
Solve the inequality for x. Show each step of the solution.<br> 4x-6(x+1)&gt;12
VLD [36.1K]
Answer:

x < - 9

steps:

4x - 6(x + 1) > 12

2x - 3(x + 1) > 6

2x - 3x - 3 > 6

2x - 3x > 6 + 3

-x > 6 + 3

-x > 9

x < -9


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8 0
3 years ago
What would 135 represent in the data set below?
Citrus2011 [14]
C. The outlier because it doesn’t fit with the rest
5 0
3 years ago
Paula finished the race at 2:14 p.m Beatrice finished the race 22 minutes earlier what time did Beatrice finish the race a 1:54
Digiron [165]

Answer: 1:52 PM

Step-by-step explanation:

PAULA: 2:14PM FINISHED THE RACE

BEATRICE: FINISHED 22 MINUTES EARLIER THEN PAULA

YOU TAKE 2:14PM AND SUBTRACT THE 22 MINS BEATRICE RAN TO GET YOU ANSWER.

SO 2:14 -14 MINS=2:00PM 14+8=22 (THE MINS BETRICE FINISHED)

2:00-8 MINS ( REMAINING FROM THE 22 ) THEN 2:00-8 MINS =1:52

ANSWER:1:52PM

5 0
2 years ago
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
2 years ago
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