Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
The answer is -4k^2 - 21k - 20! so sorry if I’m wrong but it’s the answer I got :>
Answer:
The diameter will increase at a rate of 1/30π cm/min
Step-by-step explanation:
Here we want to calculate the rate at which the diameter will increase
Mathematically, the area of a sphere is given as;
A = 4πr^2
But r = d/2
so A = 4 * π * d/2 * d/2 = πd^2
dA/d(d) = 2πd
Thus dd/dA = 1/2πd = 1/2 * π * 15 = 1/30π
Given dA/dt = 10
Mathematically;
d(d)/dt = d(d)/dA * dA/dt
dd/dt = 1/30π * 10 = 10/30π = 1/3π cm/min
Answer: Second option.
Step-by-step explanation:
Given the folllowing Linear Equation:

You need to substitute the coordinates of each point given in the options into the equation and then evaluate.
1) Substituting
into the equation, you get:

2) Substituting the point
. you get:

3) Apply the same procedure using the point
:

4) Apply the same procedure using the point 

5) Substituting
into the equation:

Therefore, the point
is not on the given line.