Answer:
Parents: Yellow (Aarr) and Grey (AaRr)
Explanation:
Given:
allele A = yellow
allele R = black,
Heteroozygous = gray
Genotypes of the parents:
yellow (Aarr) - female
gray (AaRr) - gray
cross between these
Parents: Yellow (Aarr) and Grey (AaRr)
Gametes: (Ar, ar) and (AR, Ar, aR, ar)
F1 (Punnet square)
----|----- AR ------|------- Ar ------|------ aR -----|----- ar
Ar | AARr (gray) | AArr (yellow) | AaRr (gray) | Aarr (yellow)
ar | AaRr (gray) | Aarr (yellow) | aaRr (black) | aarr (cream)
Ratio: 3/8 yellow : 3/8 gray : 1/8 cream : 1/8 black
Answer:
a Anaphase I
b Metaphase I
c Telophase I
d Anaphase II
e Prophase I
f Telophase II
Explanation:
Prophase I begins after the DNA has been duplicated, as shown in picture e. The chromosomes are condensed, and also visible, which is apparent in picture e.
The next stage is called Metaphase I, in which the pairs of homologous chromosomes align at The the centre of the cell and the spindle fibres attach, as shown in picture b.
The pairs of chromosomes are pulled apart to opposite poles of the cell by the spindle fibres., as shown in picture a. This stage is called Anaphase I.
Then, a process called Telophase I occurs, when the cell divides into two daughter cells. One of these cells is shown in picture c.
Picture d shows the stage Anaphase II, where the spindle has attached and the chromatids are pulled to the opposite poles of the cell.
The final picture left is picture f, which shows the daughter cell at the end of meiosis II, where the nuclear envelope is reforming, as in telophase II.
Answer:
the answer for me is the third option (c)
Answer: "mutations" .
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