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geniusboy [140]

3 years ago

15

chad buys peanuts in 2 pound bags. He repackages them into bags that hold 5/6 pound of peanuts. How may 2 pound bags of peanuts

should chad buy so that he can fill the 5/6 pound bags without having nay peanuts left over.

2 answers:

Marat540 [252]3 years ago

7 0

5 bags hope this helps even though it was 4 days ago

pogonyaev3 years ago

4 0

5 bags evenly because if you need to prime factor out 6

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A5 inch x 7 inch photograph is placed inside a picture frame. Both the length and width of the frame are 2x inches larger

My name is Ann [436]

Answer:

8x+24

dimensions of the photograph

length - 7 inch

width - 5 inch

dimensions of the photo frame is 2x larger than both width and length

length - 7 + 2x

width - 5 + 2x

the perimeter is sum of all 4 sides

Perimeter = 2(7 + 2x) + 2(5 + 2x)

= 14 + 4x + 10 +4x

= 24 + 8x

correct answer is 8x+24

8 0

3 years ago

Find an equivalent ratio in simplest terms:<br> 54 : 70

Elena L [17]

Answer:

27/35.

I can break it down for you to understand if u want.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

21. Who is closer to Cameron? Explain.

pickupchik [31]

Problem 21

<h3>Answer: Jamie is closer</h3>

-----------------------

Explanation:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

$A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\$

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

$J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\$

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer: Arthur is closest to the ball</h3>

-----------------------

Explanation:

We have these key locations:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)
B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

AB
JB
CB

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

$A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\$

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

-------------

So in summary, we have these approximate segment lengths

AB = 29.1547595
JB = 41.2310563
CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0

3 years ago

Find the x intercept. (Using the equation is more accurate, but I included a graph for reference)

MariettaO [177]

For the X intercept you set y = 0 and solve for x

Y = $- \frac{8}{3}$ x + 9
0= $- \frac{8}{3}$ x + 9 subtract 9 from both sides
-9 = $-\frac{8}{3} x$ divide both sides by 3
-3 = -8x divide both sides by -8
$\frac{3}{8}$ = x

X-intercept = ( $\frac{3}{8}$ , 0)

4 0

3 years ago

Una botella pesa 1090kg cuando esta llena y 250g cuando esta vacía. ¿Cuanta masa de aceite contiene la botella?

Hitman42 [59]

Respuesta:

1089,75 kg

Explicación paso a paso:

Dado que :

Masa de embotellado lleno = 1090 kg

Masa de la botella vacía = 250 g

Masa de aceite que contiene la botella:

Expresando la masa de la botella cuando se llena en gramos:

1000 g = 1 kg

1090 kg = (1090 * 1000) = 1090000 g

La masa de aceite que contiene la botella es así:

Masa de la botella cuando está llena - masa de la botella cuando está vacía

1090000 g - 250 g = 1089750 g

Por tanto, la masa de aceite es 1089750 g

O 1089750/1000 = 1089,75 kg

7 0

3 years ago