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disa [49]
3 years ago
10

What is the center of the circle with the equation x2 + y2 – 10x – 11 = 0 ?

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0
Rearrange to standard form:-

x^2 - 10x + y^2 = 11
(x - 5)^2 - 25 + y^2 = 11
(x - 5)^2 + y^2 = 36

Center of circle = (5, 0)  and radius  = sqrt36  =  6
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What is the midpoint of AC ?
Leno4ka [110]

Answer:

A: (m + p, n + r)

Step-by-step explanation:

Midpoint \:  of  \: AC  \\ =  \bigg( \frac{2m + 2p}{2}  \:  \:  \frac{2n + 2r}{2}  \bigg) \\  \\ =  \bigg( m + p, \:  \: n + r \bigg)

5 0
3 years ago
The sum of the measures of angle x and y is 90. If the measures of angle x is 30 less than twice the measures of angle y what is
svp [43]
First set up your two equations:

x + y = 90

x = 2y - 30

Then substitute what x equals in the second equation into the first equation:

(2y -30) + y = 90

Now solve for y:

3y -30 = 90
3y = 120
y = 40

Then use y = 40 and substitute the value for y into one of your original equations and solve for x.  I'll choose the first one, but either one will work.

x+ 40 = 90
x = 50

So your solution is x = 50 and y = 40


8 0
3 years ago
100 points!! <br> Please solve question 50 in detail
SCORPION-xisa [38]

Answer:

2.62

Step-by-step explanation:

log_{b} \frac{b^{2}x^{\frac{5}{2} }}{\sqrt{y}}

First, write the square root as exponent.

log_{b} \frac{b^{2}x^{\frac{5}{2} }}{y^{\frac{1}{2}}}

Move the denominator to the numerator and negate the exponent.

log_{b}(b^{2}x^{\frac{5}{2}}y^{-\frac{1}{2}})

Use log product property.

log_{b}(b^{2}) + log_{b}(x^{\frac{5}{2}}) + log_{b}(y^{-\frac{1}{2}})

Use log exponent property.

2 log_{b}(b) + {\frac{5}{2}}log_{b}(x) - {\frac{1}{2}}log_{b}(y)

Substitute values.

2(1) + \frac{5}{2}(0.36) - \frac{1}{2}(0.56) \\2.62

4 0
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The answer is 2. I hope this helped.
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3 years ago
Whats 42/99 in simplest form.
const2013 [10]

Answer:

14/33

Step-by-step explanation:

6 0
3 years ago
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