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agasfer [191]
3 years ago
13

A colored chip is yellow on one side and red on the other. The chip was flipped 50 times and landed red side facing up 21 times.

What is the relative frequency of the chip landing with the red side facing up?
42%
58%
68%
72%
Mathematics
1 answer:
faust18 [17]3 years ago
8 0
42%

You have essentially a fraction, 21/50, which gives you a decimal of 0.42, or 42%.

(Flipped a total of 50 times, of those, it landed red side up 21 times, so 21/50)
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You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

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To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

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2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

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Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

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