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igomit [66]
3 years ago
11

What is 150 percent of 94?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

150% of 94 is 141.

<h3>Explanation:</h3><h3></h3>

There are ways to solve this problem:

1). When you have a problem with for example, 150%, 50%, you can find half of that number and then add the half to the original number:

Example 1: What is 50% of 168?

To solve this you need to find 1/2 of 168, you could divide by 2.

168 / 2 = 84. Your answer is 84.

If the question was 150%, you add the half to the regular number, 84 + 168 = 252.

<h3>Further Explanation:</h3>

-----------------------------------------------------------------------

2). You can do a proportion, (more comprehensive)

For a proportion you have to set it up as fraction bar = fraction bar.

You insert the number percent over 100, since percent is out of 100, then when you fine the word, "Of", the question is telling you to put the number after of on the 2nd fraction at the denominator.

Then, you multiply in a diagonal, the number than cannot become an diagonal is what you divide the product by. Then your  answer must be on the numerator of the 2nd fraction.

Example 1: What is 75% of 30.

You put 75 / 100 in the first fraction, then you put 30 on the bottom since it's after Of.

Next, you multiply in a diagonal, 75 / 100 = ? / 30, 30 and 75 is a diagonal, those are the 2 number we multiply, 30 x 75 = 2250, 100 is the number we divide by since it's not in a diagonal.

2250 / 100 = 22.50, you can move the decimal 2 spaces to the Left for this problem.

<h3>Solving The Problem:</h3><h3>-------------------------------------</h3>

What is 150% of 94, half of 94 is 47.

94 + 47 = 141

Check: 141 - 47 = 94. Correct.

Your answer is 141.

150 / 100 = ? / 94

94 x 150 = 14,100 / 100 = 141.

Check: 150% = 150/100 x 94 = 141. Correct

Best of Luck to you.

If you have any questions, feel free to comment below.

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Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

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Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

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b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

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