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igomit [66]
3 years ago
11

What is 150 percent of 94?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

150% of 94 is 141.

<h3>Explanation:</h3><h3></h3>

There are ways to solve this problem:

1). When you have a problem with for example, 150%, 50%, you can find half of that number and then add the half to the original number:

Example 1: What is 50% of 168?

To solve this you need to find 1/2 of 168, you could divide by 2.

168 / 2 = 84. Your answer is 84.

If the question was 150%, you add the half to the regular number, 84 + 168 = 252.

<h3>Further Explanation:</h3>

-----------------------------------------------------------------------

2). You can do a proportion, (more comprehensive)

For a proportion you have to set it up as fraction bar = fraction bar.

You insert the number percent over 100, since percent is out of 100, then when you fine the word, "Of", the question is telling you to put the number after of on the 2nd fraction at the denominator.

Then, you multiply in a diagonal, the number than cannot become an diagonal is what you divide the product by. Then your  answer must be on the numerator of the 2nd fraction.

Example 1: What is 75% of 30.

You put 75 / 100 in the first fraction, then you put 30 on the bottom since it's after Of.

Next, you multiply in a diagonal, 75 / 100 = ? / 30, 30 and 75 is a diagonal, those are the 2 number we multiply, 30 x 75 = 2250, 100 is the number we divide by since it's not in a diagonal.

2250 / 100 = 22.50, you can move the decimal 2 spaces to the Left for this problem.

<h3>Solving The Problem:</h3><h3>-------------------------------------</h3>

What is 150% of 94, half of 94 is 47.

94 + 47 = 141

Check: 141 - 47 = 94. Correct.

Your answer is 141.

150 / 100 = ? / 94

94 x 150 = 14,100 / 100 = 141.

Check: 150% = 150/100 x 94 = 141. Correct

Best of Luck to you.

If you have any questions, feel free to comment below.

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5.3 Q4
barxatty [35]

The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.

<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>

g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).

Since, it follows from the Fundamental theorem of calculus that given an integral where;

Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);

g'(x) = f(x).

Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:

g'(x) = \int\limits^{e^x}_1 2 ln(t) dt = 1

The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.

Read more on fundamental theorem of calculus;

brainly.com/question/14350153

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8 0
1 year ago
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Sphinxa [80]
The y intercept is 12
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AnnyKZ [126]

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Step-by-step explanation:

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F(x)=(-3x+2) and g(x)=(2x^2-5x-1)
pashok25 [27]

Answer: -6x² + 15x + 5

Step-by-step explanation:

To solve this problem, you only need to substitute g(x)'s equation as the value of the x in f(x), then simplify.

Step 1: f(x) = -3(2x² - 5x - 1) + 2

Step 2: Apply the distributive property

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Step 3: Simplify

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f(x) = -6x² + 15x + 5

6 0
3 years ago
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