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3 years ago

What is 150 percent of 94?

Mathematics

1 answer:

dmitriy555 [2]3 years ago

6 0

Answer:

150% of 94 is 141.

<h3>Explanation:</h3><h3></h3>

There are ways to solve this problem:

1). When you have a problem with for example, 150%, 50%, you can find half of that number and then add the half to the original number:

Example 1: What is 50% of 168?

To solve this you need to find 1/2 of 168, you could divide by 2.

168 / 2 = 84. Your answer is 84.

If the question was 150%, you add the half to the regular number, 84 + 168 = 252.

<h3>Further Explanation:</h3>

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2). You can do a proportion, (more comprehensive)

For a proportion you have to set it up as fraction bar = fraction bar.

You insert the number percent over 100, since percent is out of 100, then when you fine the word, "Of", the question is telling you to put the number after of on the 2nd fraction at the denominator.

Then, you multiply in a diagonal, the number than cannot become an diagonal is what you divide the product by. Then your answer must be on the numerator of the 2nd fraction.

Example 1: What is 75% of 30.

You put 75 / 100 in the first fraction, then you put 30 on the bottom since it's after Of.

Next, you multiply in a diagonal, 75 / 100 = ? / 30, 30 and 75 is a diagonal, those are the 2 number we multiply, 30 x 75 = 2250, 100 is the number we divide by since it's not in a diagonal.

2250 / 100 = 22.50, you can move the decimal 2 spaces to the Left for this problem.

<h3>Solving The Problem:</h3><h3>-------------------------------------</h3>

What is 150% of 94, half of 94 is 47.

94 + 47 = 141

Check: 141 - 47 = 94. Correct.

Your answer is 141.

150 / 100 = ? / 94

94 x 150 = 14,100 / 100 = 141.

Check: 150% = 150/100 x 94 = 141. Correct

Best of Luck to you.

If you have any questions, feel free to comment below.

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andreev551 [17]

Answer:

The correct option is the option with:

cos Θ = 1/2

tan Θ = -√3

Step-by-step explanation:

Given that

sin Θ = -√3/2

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cos Θ and tan Θ

First of all,

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tan Θ = (sin Θ)/(cos Θ)

tan Θ = (-√3/2)/(cos Θ)

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Knowing that Θ = -60,

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cos Θ = 1/2

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3 years ago

Read 2 more answers

7. Consider the purchase of two cereal boxes.

AveGali [126]

Answer:

a) 0.25

b) 0.25

c) 0.0625

Step-by-step explanation:

The complete question is:

Do you remember when breakfast cereal companies placed prizes in boxes of cereal? Possibly you recall that when a certain prize or toy was particularly special to children, it increased their interest in trying to get that toy. How many boxes of cereal would a customer have to buy to get that toy? Companies used this strategy to sell their cereal.

One of these companies put one of the following toys in its cereal boxes: a block (B), a toy watch (W), a toy ring (R), and a toy airplane (A). A machine that placed the toy in the box was programmed to select a toy by drawing a random number of 1 to 4. If a 1 was selected, the block (or B) was placed in the box; if a 2 was selected, a watch (or W) was placed in the box; if a 3 was selected, a ring (or R) was placed in the box; and if a 4 was selected, an airplane (or A) was placed in the box. When this promotion was launched, young children were especially interested in getting the toy airplane.

What is the probability of getting an airplane in the first cereal box?

Since the machine randomly selects toys, each toy has the same probability of being obtained in a cereal box.

Then, the total outcomes are 4 and the probability of getting an airplane in the first cereal box is 0.25 (25%).

What is the probability of getting an airplane in the second cereal box?

Two independent events do not change the probability of occurrence of one event or another.

The probability of getting an airplane in the second cereal box is 0.25 (25%).

What is the probability of getting airplanes in both cereal boxes?

P(1°∩2°)= P(1°) × P(2°) = $\frac{1}{4} \times \frac{1}{4} =\frac{1}{16}$

P(1°∩2°)= 0.0625 = 6.25%

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(a)

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(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent <em>p</em>-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

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3 years ago