Answer:
A fair die has 6 sides.
There are 3 odd numbers on a fair die so the probability would be 3/6
There are 4 numbers greater than 2 on a fair die o the probability of that would be 4/6
There is only one number that will make it square and that is 4. So the probability would be 1/6
Answer:
D
Step-by-step explanation:
I just did this lol
Y=-2sin((2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
<span>/7)x)
y = asin(bx+c)+d and t</span>he period is given by the equation T = 2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
/b
where T is the period of the function. "a" changes the amplitude only (vertical stretch). ""c" is the left/right phase shift. "d" moves the whole graph up or down.
The coefficient of x in (2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
/7)x is 2 pi/7 which would also be equal to b.
T = 2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
/(2
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
/7) = 7
I can help you do you want help?