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allochka39001 [22]
3 years ago
15

Given the pattern 3,10,17,24..the nth term could be represented by which of the following?

Mathematics
1 answer:
vredina [299]3 years ago
8 0
Prob 31 cause it goes up by 7 each time
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Give ur answer in standard form. <br>3 x 10^4 ÷6 x 10^-4<br>​
Anni [7]

Answer:

5.0×10⁷

Step-by-step explanation:

(3÷6)×(10⁴÷10^-4)

(0.5)×(10⁸)

5.0×10^-1×10⁸

5.0×10⁷

7 0
2 years ago
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In one week, Callum collected 1246 rocks from the seashore. Every day, he collected the same number of rocks. In a single day, h
Snezhnost [94]

Answer:

178

Step-by-step explanation:

1246 over a week, (1246/7) in a day. 178 rocks a day

6 0
3 years ago
There are nickels, dimes, quarters in a large piggy bank, for every 2 nickels there are 3 dimes, for every 2 dimes there are 5 q
Alex

There are 80 nickels and 120 dimes and 300 quarters in piggy bank

<em><u>Solution:</u></em>

Given that,

For every 2 nickels there are 3 dimes ,

So, ratio of nickel to dime will be 2 : 3

Also for every 2 dimes there are 5 quarters

So, ratio of dime to quarters is 2 : 5

Let us first find the ratio of nickles to dimes to quarters

nickel : dime = 2 : 3

dime : quarters = 2 : 5

\frac{nickel}{dime} = \frac{2}{3}

nickel = \frac{2}{3} dime

\frac{dime}{quarter} = \frac{2}{5}

quarter = \frac{5}{2}dime

So,

nickel : dime : quarter = \frac{2}{3}dime : dime : \frac{5}{2}dime\\\\nickel : dime : quarter = \frac{2}{3} : 1 : \frac{5}{2}\\\\nickel : dime : quarter = 4 : 6 : 15

Thus nickel : dime : quarters = 4 : 6 : 15

Now, let the number of nickel be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

From given question,

There are 500 coins in all.

number of nickel + number of dimes + number of quarters = 500

4x + 6x + 15x = 500

25x = 500

x = 20

Thus,

number of nickel = 4x = 4(20) = 80

number of dimes = 6x  = 6(20) = 120

number of quarters = 15x = 15(20) = 300

Thus there are 80 nickels and 120 dimes and 300 quarters in piggy bank    

3 0
3 years ago
What is the product of (2p+7)(3p+4p-3)
Alex

Answer:

The answer is C=6p3 + 29p2 + 22p – 21

Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3

                                   =    6p³     +     8p²    -     6p    + 21p²   +  28p   -     21

                                   = 6p³ + 8p² + 21p² + 28p - 6p -21

                                   = 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21

3 0
3 years ago
Read 2 more answers
At which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptote? Check all that apply
pychu [463]

vertical asymptotes: x=-4 , x=1 , x=4

6 0
3 years ago
Read 2 more answers
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