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Rom4ik [11]
3 years ago
6

Solve: -7(3+6x)=9(-5x+7)

Mathematics
2 answers:
Ivan3 years ago
7 0

Answer:

x=28

Step-by-step explanation:

-7(3+6x)=9(-5x+7)

-21-42x=-45x+63

-21-42x-(-45x)=63

-21-42x+45x=63

-21+3x=63

3x=63-(-21)

3x=63+21

3x=84

x=84/3

x=28

12345 [234]3 years ago
4 0

Answer:

x=28

Step-by-step explanation:

-7(3+6x) = 9(-5x+7)

-21-42x=-45x+63

-42x=-45x+84

3x=84

x=28

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What is the domain of the function =<br> x+6-7?<br> x2-7<br> X2-6<br> x26<br> Ox27
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8 0
4 years ago
Rearrange the formula V = 1 3 πr2h for h. A) h = 3V πr2 B) h = V 3πr2 C) h = 3πr2 V D) h = πr2 3V
stiks02 [169]

Answer:

Option a) h=\frac{3V}{\pi r^{2} }

Step-by-step explanation:

The given formula seems to represent the volume of right circular cone. The correct formula is:

V=\frac{1}{3} \pi r^{2} h

We have to rearrange the formula for h. This means we have to move h on one side of the formula and all the other variables and constants on the other side of the equation. This can be done as shown below:

V=\frac{1}{3} \pi r^{2} h\\\\3V=\pi r^{2} h\\\\h=\frac{3V}{\pi r^{2} }

5 0
4 years ago
Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but
grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

\frac{8km}{55min}=.145\frac{km}{min} and we can use that in a d = rt table:

                 d        =        r        *        t

Nina                            .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

                d        =        r       *        t

Nina         6        =     .145

Jo             6        =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

                d        =        r        *        t

Nina          6       =       .145    *      t + 3

Jo              6       =         r       *         t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0
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12/5 = 2.40

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